Question

What is the potential difference between xi=2.0m and xf=3.0m?

Answer 1

Answer:

$\Delta E=100$

Explanation:

To find the potential difference between $x_{i}=2.0m$ and $x_{f}=3.0m$, we just need to observe which vertical coordinates belong to these given values.

From the graph, we observe that $x_{i}=2.0m$ correspond to $E_{i}=100$, because they form the point $(2,100)$ which is given in the graph.

With the same reasoning, we observe that $E_{f}=200$ corresponds to $x_{f}=3.0m$, because they both together form the points $(3,200)$.

Now, the potential difference between the given distances, we just need to subtract

$\Delta E=E_{f} -E_{i}=200-100=100$

Which also refers to the variation of the potential.

Therefore, the potential differential is $\Delta E=100$

Answer 2

From the graph given, the y-axis represents the potential energy while the x axis is represents the displacement. To calculate the potential difference, I think the values from point two to point one should be only subtracted.

Potential difference = 200 - 100 = 100 V/m