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IrinaK [193]
3 years ago
15

What causes a nebula to collapse into a dense mass?

Physics
1 answer:
bekas [8.4K]3 years ago
6 0
The answer is <span>Gravity.

</span>  Irregularities in the density of the gas causes a net gravitational force

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A coin completes 18 spins in 12 seconds. The centripetal acceleration of the edge of the coin is 2.2 m/s2. The radius of the coi
stellarik [79]

Answer:

2.5 cm

Explanation:

Number of spins in 12 seconds = 18

Number of spins in 1 second = 18 / 12 = 1.5

Number of spins in one second is called frequency.

f = 1.5 rps

ac = 2.2 m/s^2

Let r be the radius of coin

Centripetal acceleration, ac = r x w^2

2.2 = r x ( 2 x 3.14 x 1.5) ^2

2.2 = r x 88.7364

r = 0.025 m = 2.5 cm

3 0
4 years ago
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A man weighing 980 n on earth
Alla [95]

Answer:

91.84kg

Explanation:

6 0
3 years ago
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A stone is thrown vertically upward with a speed of 28.0 m/s how much time is required to reach this height
Solnce55 [7]
A stone is thrown vertically upward with a speed of 17.0 m/s. How fast is it moving when it reaches a height of 11.0 m? How long is required to reach this height?

Let’s review the 4 basic kinematic equations of motion for constant acceleration (this is a lesson – suggest you commit these to memory):

s = ut + ½ at^2 …. (1)

v^2 = u^2 + 2as …. (2)

v = u + at …. (3)

s = (u + v)t/2 …. (4)

where s is distance, u is initial velocity, v is final velocity, a is acceleration and t is time.

In this case, we know u = 17.0m/s, a = -g = -9.81m/s^2, s = 11.0m and we want to know v and t, so from equation (2):

v^2 = u^2 + 2as

v^2 = 17.0^2 -2(9.81)(11.0)

v = √73.18 = 8.55m/s

now from equation (3):

v = u + at

8.55 = 17.0 – 9.81t

t = (8.55 – 17.0)/(-9.81) = 0.86s
6 0
3 years ago
Would this be 2N because 6 and 4 cancel out? Or no because 4 plus two is six and that cancels everything out to 0
soldier1979 [14.2K]

Answer: It would be 0

Explanation: Because like you said it would cancel each other out because if you are going 6N to the right and then you go 6N to the left you are actually not moving at all  

5 0
3 years ago
An astronaut named Speedo takes a trip to Sirius, which is located a distance of 8 lightyears from the Earth. If the spaceship m
Softa [21]

Answer:

<em>a. 10 years</em>

<em>b. 6 years</em>

<em>c. 12 years behind</em>

<em></em>

Explanation:

speed of light c =  3x10^{8} m/s

distance of sirius from earth = 8 lightyears = 8 x c x 60 x 60 x 24 x 365 = 252288000c meters

speed of spaceship = 0.8c

time taken to reach sirius = distance covered divided by speed

t = d/s = 252288000c/0.8c = 315360000 sec

<em>1 year = 60 x 60 x 24 x 365 sec = 31536000 sec</em>

315360000 sec = 315360000/31536000 = <em>10 yrs</em>

<em>the time as observed by Goslo will be shorter than the real time as measured within the ship due to relativistic effects. using the relativistic relation for time dilation we have</em>

t' = t\sqrt{1 - \frac{v^{2} }{c^{2} } }

since v = 0.8c

v/c = 0.8

where t' is the relativistic time as observed by Goslo,

t is the time within the ship

t' = 10 x \sqrt{1 - 0.8^{2}  }  = <em>6 yrs</em>

<em></em>

If speedo turns around immediately after reaching  sirius, his total distance will be 252288000c x 2 = 50457600c meter

time taken = 50457600c/0.8 = 630720000 sec = 20 yrs

time within the ship will be calculated from time dilation

t' = t\sqrt{1 - \frac{v^{2} }{c^{2} } }

t' = 20 x  \sqrt{1 - 0.8^{2}  }  = 378432000 sec = <em>12 years behind</em>

4 0
3 years ago
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