Determine the empirical formula for a compound that contains 48.6%C, 8.2% H, and 43.2% S by mass.
1 answer:
The empirical formula for a compound that contains 48.6%C, 8.2% H, and 43.2% S by mass is .
An empirical formula tells us the relative ratios of different atoms in a compound.
We need to calculate the number of moles
Number of a mole of carbon =
48.6 g X () =4.05 mole
Number of a mole of hydrogen =
8.2g X () =8.14 mole
Number of moles of sulphur =
43.2g X () = 1.35 mole
Dividing each mole using the smallest number that is divided by 1.35 moles.
Carbon= =3
Oxygen= =6
Sulfur= =1
Empirical formula is
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Answer:
El potencial celular estándar, is +0.46 V
Explanation:
Las reacciones de media célula son;
Media reacción del ánodo Cu²⁺ + 2e⁻ ↔ Cu, E ° = 0.34 V
Media reacción catódica 2Ag + 2e⁻ ⁻ 2Ag, E ° = 0.80 V
Sin embargo tenemos para hierro Fe²⁺ + 2e⁻ ↔ Fe, E ° -0.44 V
y Fe³⁺ + e⁻ ↔ Fe²⁺, E ° = 0.77 V
que es más alta que la del cobre presente, por lo tanto, el cobre se oxidará en el ánodo
Por lo tanto, en el ánodo, tendremos
Cu → Cu²⁺ + 2e⁻ (E ° = -0.34 V)
En el cátodo
2Ag + 2e⁻ → 2Ag (E ° = 0.80 V)
El potencial celular estándar, = +0.46 V
Answer:
e. None of these.
Explanation:
Hey there!
In this case, since the Henry's law is defined in terms of pressure, henry's constant and pressure, as shown below:
Whereas C is the concentration, KH the Henry's constant and P the pressure, we infer that the concentration of a gas solution is directly proportional to the pressure, which is not the group choices, therefore, the answer is e. None of these.
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