Question

Determine the empirical formula for a compound that contains 48.6%C, 8.2% H, and 43.2% S by mass.

Answer 1

The empirical formula for a compound that contains 48.6%C, 8.2% H, and 43.2% S by mass is $C_3H_6S$.

What is the empirical formula?

An empirical formula tells us the relative ratios of different atoms in a compound.

We need to calculate the number of moles

Number of a mole of carbon =

48.6 g X ($\frac{1 mole }{ 12.0107 g}$) =4.05 mole

Number of a mole of hydrogen =

8.2g X ($\frac{1 mole}{.00784g}$) =8.14 mole

Number of moles of sulphur =

43.2g X ($\frac{ mole}{32.065g}$) = 1.35 mole

Dividing each mole using the smallest number that is divided by 1.35 moles.

Carbon= $\frac{4.05 mole }{1.35 mole}$ =3

Oxygen= $\frac{8.14 mole}{1.35 mole}$ =6

Sulfur= $\frac{1.35 mole}{1.35 mole}$ =1

Empirical formula is $C_3H_6S$

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