A B C D 1) NaNH2 2) MeI 3) 9-BBN 4) H2O2, NaOH 1) Br2 2) Excess NaNH2 3) H2O 1) Br2 2) Excess NaNH2 3) H2O 4) H2SO4, H2O, HgSO4
1) NaNH2 2) EtI 3) Na, NH3 (l) E F G H 1) 9-BBN 2) H2O2, NaOH 1) Excess NaNH2 2) H2O 3) Br2 (1 eq), CCl4 1) Excess NaNH2 2) H2O 3) NaNH2 4) MeI 5) Na, NH3 (l) 1) NaNH2 2) 3) H2, Pt
1 answer:
Answer:
The question has some part missing which I have added in the attachment.
Explanation:
The reactions given occur under certain reagents, which we are told to pick for each of the reaction synthesis. Conventionally, halogens have the ability to undergo addition reactions with hydrocarbons by breaking down the double or triple bond in them to a single bond, this usually occur by electron donation and electron acceptor.
The attachment shows the reactions and the necessary reagents required for each
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Answer:
Explanation:
Given
Required
Determine the final mass
First we need to determine the total mass after the sample mass is added to an additional sample;
Next, divide the total mass by 3
The final mass is calculated as follows;
<em>Hence, the final mass is 17.560943085g</em>
Answer:
32.7 grams of Zn will remained in the crucible after cooling.
Explanation:
..[1]
..[2]
Adding [1] + 2 × [2] we get:
..[3]
Moles of ZnS in crucible = 0.50 mol
According to reaction [3]. 2 moles of ZnS gives 2 moles of Zn.
Then 0.50 moles of ZnS will give:
of Zn.
Mass of 0.50 moles of Zn =
= 0.50 mol × 65.4 g/mol =32.7 g
32.7 grams of Zn will remained in the crucible after cooling.