Answer:
F = 4.47 10⁻⁶ N
Explanation:
The expression they give for the strength of the tide is
F = 2 G m M a / r³
Where G has a value of 6.67 10⁻¹¹ N m² / kg² and M which is the mass of the Earth is worth 5.98 10²⁴ kg
They ask us to perform the calculation
F = 2 6.67 10⁻¹¹ 135 5.98 10²⁴ 13 / (6.79 10⁶)³
F = 4.47 10⁻⁶ N
This force is directed in the single line at the astronaut's mass centers and the space station
<u>Answer:</u>
Magnitude of δv = 80.78 m/s
Angle , θ =
<u>Explanation:</u>
Here east direction is zero degree, that is zero degree is along positive X direction, north is along + Y direction, West is along - X direction and South is along -Y direction.
In this case initial velocity = 30.0 m/s south = -30 j
Final velocity = 75.0 m/s west = - 75 i
We know that change in velocity = Initial velocity - Final velocity
So δv = - 75 i - (-30 j)
= - 75 i + 30 j m/s
Magnitude of δv =
Angle , θ =
Answers; Formed of ice, rock and dust
Develop tails near the sun
Answer:
<h2><u>Given </u><u>:</u><u>-</u></h2>
mass = 65 kg
Height = 80 m
Acceleration = 9.8 m/s²
<h2><u>To </u><u>Find</u><u> </u><u>:</u><u>-</u></h2>
Potential energy
<h2><u>Solution</u><u> </u><u>:</u><u>-</u></h2>
We know that
PE = mass × acceleration × height
PE = 65 × 80 × 9.8
PE = 50,960 Joules
Answer:
Explanation:36.05 km
Given
First car travels South
then turns and travels east
Suppose south as negative y axis and east as positive x axis
So,
Displacement is the shortest between initial and final point
Dispalcement
Displacement
Displacement
Magnitude
Magnitude