Answer:
Incomplete question
This is the completed question
If the resistor in the circuit had a larger resistance then the current would be then have to be proportionally smaller. Because the batteries each give off 1.5 volts then the current would have to be the variable that would change. What affect would using a 12V car battery have on the operation of your circuit? (Do not try this.) What would happen to the current? What would happen to the resistor?
Explanation:
Using ohms law as our basis
Ohms law state that, the voltage in an ohmic conductor is directly proportional to the current
V∝I
Resistance is the constant of proportionality
Then
V=iR
Since we want a relationship between current and resistance.
then, I=V/R
So, current is inversely proportional to Resistance
as the current increase the resistance reduce and as the current reduces the resistance increases.
a. So, increasing the voltage from 1.5V to 12V increases the current In the circuit because voltage Is directly proportional to I.
From ohms law
V=iR
When v =1.5V
I=1.5/R
When V increase to 12V
I=12/R
I.e, it increases by a factor of 8. Eight times it's initial value
b. Now, the resistance in the circuit is the constant of proportionality and it doesn't change in a given circuit expect when using a variable resistoa r like rheostat.
Answer:
heart failure, heart attack,
Explanation:
heart failure, heart attack,
Explanation:
when an object speeds up,it has positive acceleration.
hope it helps....
Explanation:
It is given that,
A helicopter blade spins at exactly 100 revolutions per minute.
Its tip is 5.00 m from the center of rotation, r = 5 m
(a) Let v is the average speed of the blade tip in the helicopter’s frame of reference. Distance covered by the helicopter, 
In 100 revolutions, 
So, average speed of the blade tip in one second is given by :
v = 52.35 m/s
(b) The average velocity over one revolution is zero because the net displacement in one rotation is 0.
Hence, this is the required solution.
