Answer:
141.78 ft
Explanation:
When speed, u = 44mi/h, minimum stopping distance, s = 44 ft = 0.00833 mi.
Calculating the acceleration using one of Newton's equations of motion:
Note: The negative sign denotes deceleration.
When speed, v = 79mi/h, the acceleration is equal to when it is 44mi/h i.e. -116206.48 mi/h^2
Hence, we can find the minimum stopping distance using:
The minimum stopping distance is 141.78 ft.
1. Weight is the gravitational pull with which the earth attracts the body towards the center of the earth. The S.I unit is Newton (N)
2. The weight of an object is related to its mass with the below equation.
W = mg
Where W = weight, m = mass and g = acceleration due to gravity
3. The mass m = 50 kg and g = 9.8 m/
Substitute the parameters in the equation above.
W = 50 x 9.8
W = 490 N
4. An object is accelerating when it speeds up. If the object slows down, it means it is decelerating. The correct answer is option A
5. Newton's second law of motion is:
F = ma
Where F = force applied, m = mass and a = acceleration
Therefore, Newton's second law of motion relates an object's acceleration to its net force acting on it. The correct answer is option C
6. According to Newton's second law of motion which relates an object's acceleration to its mass, doubling the net force acting on an object a doubles its acceleration. Because mass is always constant.
7. Since the weight of an object is related to its mass with the equation.
W = mg, If the mass of an object doubles, its weight will also doubles. Option A is the correct answer.
8. If you know the mass of an object, you can calculate its weight with the formula F = mX when X = 9.8m/
9. Force is expressed in unit as Newton (N)
10. The parameters given are :
mass m = 20kg
Force F = 40N
To calculate acceleration, use the formula F = ma
Substitute all the parameters into the equation.
40 = 20a
a = 40/20
a = 2m/
The correct option is D
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