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Maksim231197 [3]
3 years ago
14

How much force is needed to stop a 120-kg ice-hockey player if he decelerates at 20 m/s²?

Physics
1 answer:
Troyanec [42]3 years ago
3 0

ANY force at all, acting in the right direction, will stop him. 
But smaller forces will take longer.

In order to either speed him up or slow him down at the rate
of 20 m/s every second, the force required is

           (mass) x (acceleration) = (120 kg) x (20 m/s²)

                                               = (2400 kg-m/s²) = 2400 N .

The force can either increase or decrease his speed at that rate,
depending on the direction in which it acts on him.

If the force is exerted opposite to the direction in which he's already
moving, then it can stop him if it continues long enough. 

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Suppose you fill two rubber balloons with air, suspend both of them from the same point, and let them hang down on strings of eq
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The force on each balloon is 2×10^−3 N.

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F_{e}  = \frac{mg}{cos10\textdegree }sin10\textdegree  = mgtan10\textdegree \\\\= (0.00100kg)(9.8m/s^{2})tan10\textdegree \\\\F_{e} = 2 \times 10^{-3}N

A force is an influence that can change the motion of an object. A force can cause an object with mass to change its velocity (e.g. moving from a state of rest), i.e., to accelerate. Force can also be described intuitively as a push or a pull. A force has both magnitude and direction, making it a vector quantity. It is measured in the SI unit of newton (N).

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3 0
1 year ago
А
timurjin [86]

Answer:

i hope it will be useful for you

Explanation:

F=5.6×10^-10N

R=93cm=0.93m

let take m1 and m2 =m²

according to newton's law of universal gravitation

F=m1m2/r²

F=m²/r²

now we have to find masses

F×r²=m²

5.6×10^10N×0.93m=m²

5.208×10^-9=m²

taking square root on b.s

√5.208×10^-9=√m²

so the two masses are m1=7.2×10^-5

and m2=7.2×10^-5

8 0
3 years ago
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