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Maksim231197 [3]
3 years ago
14

How much force is needed to stop a 120-kg ice-hockey player if he decelerates at 20 m/s²?

Physics
1 answer:
Troyanec [42]3 years ago
3 0

ANY force at all, acting in the right direction, will stop him. 
But smaller forces will take longer.

In order to either speed him up or slow him down at the rate
of 20 m/s every second, the force required is

           (mass) x (acceleration) = (120 kg) x (20 m/s²)

                                               = (2400 kg-m/s²) = 2400 N .

The force can either increase or decrease his speed at that rate,
depending on the direction in which it acts on him.

If the force is exerted opposite to the direction in which he's already
moving, then it can stop him if it continues long enough. 

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a) directly related.

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4 years ago
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What is the strength of the electric field 0.1 mmmm below the center of the bottom surface of the plate
Aleksandr [31]

Complete Question

A thin, horizontal, 12-cm-diameter copper plate is charged to 4.4 nC . Assume that the electrons are uniformly distributed on the surface. What is the strength of the electric field 0.1 mm above the center of the top surface of the plate?

Answer:

The  values is  E =248.2 \  N/C

Explanation:

From the question we are told that

   The  diameter is  d =  12 \  cm  =  0.12 \ m

    The charge  is  Q =  4.4 nC  =  4.4 *10^{-9} \  C

    The  distance from the center  is  k =  0.1 \ mm   =  1*10^{-4} \  m

Generally the radius is mathematically represented as

        r =  \frac{d}{2}

=>     r =  \frac{0.12}{2}

=>       r =  0.06 \  m

Generally electric field is mathematically represented as  

       E =  \frac{Q}{ 2\epsilon_o } [1 - \frac{k}{\sqrt{r^2 +  k^2 } } ]

substituting values  

      E =  \frac{4.4 *10^{-9}}{ 2* (8.85*10^{-12}) } [1 - \frac{(1.00 *10^{-4})}{\sqrt{(0.06)^2 +  (1.0*10^{-4})^2 } } ]

     E =248.2 \  N/C

4 0
3 years ago
A brave but inadequate rugby player is being pushed backward by an opposing player who is exerting a force of 780 N on him. The
stich3 [128]

Answer:

f = 556.4 N

Explanation:

Mass of the losing player with its all equipment is given as

M = 86 kg

Net force applied on him by another player is given as

F = 780 N

also we know that acceleration of the losing player is given as

a = 2.6 m/s^2

now by Newton's 2nd law we will have

F - f = ma

780 - f = 86(2.6)

780 - f = 223.6

f = 556.4 N

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3 years ago
A truck is traveling 70.0 kph away from you. The driver is blowing the horn, which has a frequency of 400 Hz. The air temperatur
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Use this site is better https://www.cymath.com/
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3 years ago
Please help me
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Answer:

This motion is known as Brownian motion.

Explanation:

This motion is known as Brownian motion.

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