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nekit [7.7K]
3 years ago
14

A graph titled Position versus time for with horizontal axis time (seconds) and vertical axis position (meters). The line runs i

n 3 straight segments from 0 seconds 0 meters to 4 seconds 12 meters to 6 seconds 12 meters to 12 seconds 0 meters.
Use the graph to determine the velocity between 6 and 12 seconds.



m/s

A -2

B -1

C 0

D 1

E 2

What was the velocity over the entire trip?


A -2

B -1

C 0

D 1

E 2

m/s
Physics
2 answers:
Lelu [443]3 years ago
8 0

Answer:

The first one is 3 m/s

The second one is 2 m/s

Explanation:

MrRa [10]3 years ago
8 0

Answer:

the first one is -2 and the second one is 0

Explanation:

got it correct on edge 2020

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A Hall probe, consisting of a rectangular slab of current-carrying material, is calibrated by placing it in a known magnetic fie
Citrus2011 [14]

Answer:

(a) 0.345 T

(b) 0.389 T

Solution:

As per the question:

Hall emf, V_{Hall} = 20\ mV = 0.02\ V

Magnetic Field, B = 0.10 T

Hall emf, V'_{Hall} = 69\ mV = 0.069\ V

Now,

Drift velocity, v_{d} = \frac{V_{Hall}}{B}

v_{d} = \frac{0.02}{0.10} = 0.2\ m/s

Now, the expression for the electric field is given by:

E_{Hall} = Bv_{d}sin\theta                            (1)

And

E_{Hall} = V_{Hall}d

Thus eqn (1) becomes

V_{Hall}d = dBv_{d}sin\theta

where

d = distance

B = \frac{V_{Hall}}{v_{d}sin\theta}                      (2)

(a) When \theta = 90^{\circ}

B = \frac{0.069}{0.2\times sin90} = 0.345\ T

(b) When \theta = 60^{\circ}

B = \frac{0.069}{0.2\times sin60} = 0.398\ T

5 0
3 years ago
17. Matthew has a piece of wood with mass of 278 g and a volume of 375 cm^3. What is the wood’s density? a. Step 1: Formula ____
Keith_Richards [23]

Answer:

Density =0.74 g/cm^{3}

Explanation:

Step 1: Formula

 Density=\frac{Mass}{Volume}

Step 2: Data

m=278 g

v=375 cm^{3}

Step 3:Solve

d= \frac{278}{375} g/cm^{3}

d=0.74 g/cm^{3}

8 0
3 years ago
The pupil of a cat's eye narrows to a slit width of 0.5 mm in daylight. What is the angular resolution of the cat's eye in dayli
Elenna [48]

Answer:

C. 10⁻³ rads

Explanation:

Here, we shall use Rayleigh's Criterion to find out the angular resolution of Cat's eye during day light. Rayleigh's Criterion is written as follows:

θ = λ/a

where,

θ = angular resolution of Cat's eye = ?

λ = wavelength = 500 nm = 5 x 10⁻⁷ m

a = slit width of eye = 0.5 mm = 5 x 10⁻⁴ m

Therefore,

θ = (5 x 10⁻⁷ m/5 x 10⁻⁴ m)

Therefore,

θ = 0.001

θ = Sin⁻¹(0.001)

θ = 0.001 rad = 1 x 10⁻³ rad

Hence, the correct answer is:

<u>C. 10⁻³ rads</u>

4 0
3 years ago
A negatively charged plastic comb is brought close to, but does not touch, a small piece of paper. If the comb and the paper are
Irina-Kira [14]

If the comb and the paper are attracted to each other the charge on the paper, is D)must be positive

<h3>Laws of electrical attraction</h3>

This states that

  • Like charges attract
  • Unlike charges repel

Now, given that a negatively charged plastic comb is brought close to, but does not touch, a small piece of paper. If the comb and the paper are attracted to each other the charge on the paper, this implies that both the negatively charged plastic comb and the paper have opposite charges.

Since the charge on the plastic comb is negative, this means that the charge on the paper must be positive

So, if the comb and the paper are attracted to each other the charge on the paper, is D)must be positive

Learn more about electric charge here:

brainly.com/question/2373424

4 0
2 years ago
4.
Pie

Answer:

b

Explanation:

it compresses hot air turning into cool air almost like a reverse tornado

3 0
3 years ago
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