Explanation:
It is given that,
Force on grindstone, F = 180 N
Radius of grindstone, r = 0.28 m
Mass of grindstone, m = 75 kg
We need to find the angular acceleration of the grindstone. In rotational motion, the relation between the torque and angular acceleration is given by :
![\tau=I\times \alpha](https://tex.z-dn.net/?f=%5Ctau%3DI%5Ctimes%20%5Calpha)
![\alpha=\dfrac{\tau}{I}](https://tex.z-dn.net/?f=%5Calpha%3D%5Cdfrac%7B%5Ctau%7D%7BI%7D)
I is the moment of inertia of solid disk, ![I=\dfrac{1}{2}mr^2](https://tex.z-dn.net/?f=I%3D%5Cdfrac%7B1%7D%7B2%7Dmr%5E2)
is the torque exerted, ![\tau=F\times r](https://tex.z-dn.net/?f=%5Ctau%3DF%5Ctimes%20r)
![\alpha=\dfrac{F\times r}{\dfrac{1}{2}mr^2}](https://tex.z-dn.net/?f=%5Calpha%3D%5Cdfrac%7BF%5Ctimes%20r%7D%7B%5Cdfrac%7B1%7D%7B2%7Dmr%5E2%7D)
![\alpha=\dfrac{2F}{mr}](https://tex.z-dn.net/?f=%5Calpha%3D%5Cdfrac%7B2F%7D%7Bmr%7D)
![\alpha=\dfrac{2\times 180\ N}{75\ kg\times 0.28\ m}](https://tex.z-dn.net/?f=%5Calpha%3D%5Cdfrac%7B2%5Ctimes%20180%5C%20N%7D%7B75%5C%20kg%5Ctimes%200.28%5C%20m%7D)
![\alpha =17.14\ rad/s^2](https://tex.z-dn.net/?f=%5Calpha%20%3D17.14%5C%20rad%2Fs%5E2)
So, the angular acceleration of the disk is
. Hence, this is the required solution.
Answer:
he will not be drowned
Explanation:
Question says , the height of the student = 4 feet,
Depth of the pool( in feet ) be x ( say ) which is less than 4 feet,
Clearly, the depth of the pool < height of the student,
This means, if the student goes for swimming in the pool, however he does not know swimming, he will not be drowned until he is suffering from an injury or external force.
mercury??????? my only guess
<span>The weight of the rock is 138n when accelerating downward at 3.5m/ s2.Weight is a measurement of the force of gravity on an objects mass. Therefore as long as the force of gravity is the same and the mass of the rock is the same the weight should also be the same.</span>