All categories

3 years ago

A chemist weighed out 101. g of mercury. calculate the number of moles of mercury she weighed out

1 answer:

3 0

0.504 moles First look up the atomic weight of mercury. atomic weight of mercury = 200.59 Then divide the mass of the mercury you have by it's atomic weight 101 / 200.59 = 0.503515 So you have 0.503515 moles of mercury. Round the result to 3 significant digits giving you 0.504 moles.

You might be interested in

When iron reacts with oxygen what substance is produced?

zhannawk [14.2K]

It will produce iron oxide

8 0

3 years ago

. A reaction in which A, B, and C react to form products is first order in A, second order in B, and zero order in C. a) Write a

AleksAgata [21]

Answer:

a) r = k × [A] × [B]²

b) 3

Explanation:

Let's consider the following generic reaction

A + B + C ⇒ Products

The generic rate law is:

r = k × [A]ᵃ × [B]ᵇ × [C]ⁿ

where

r: reaction rate

k: rate constant

a, b, n: reaction orders

This reaction is first order in A, second order in B, and zero order in C. The rate law is:

r = k × [A]¹ × [B]² × [C]⁰

r = k × [A] × [B]²

The overall order of the reaction is the sum of the individual reaction orders.

1 + 2 + 0 = 3

4 0

3 years ago

How many carbon atoms are there in .500 mol of CO2?

AURORKA [14]

Answer: There are $3.011 \times 10^{23}$ atoms present in 0.500 mol of $CO_{2}$ .

Explanation:

According to the mole concept, there are $6.022 \times 10^{23}$ atoms present in 1 mole of a substance.

In a molecule of $CO_{2}$ there is only one carbon atom present. Therefore, number of carbon atoms present in 0.500 mol of $CO_{2}$ are as follows.

$1 \times 0.500 \times 6.022 \times 10^{23}\\= 3.011 \times 10^{23}$

Thus, we can conclude that there are $3.011 \times 10^{23}$ atoms present in 0.500 mol of $CO_{2}$ .

6 0

3 years ago

WHAT CAUSES THE MOVEMENT OF THESE AIR PARTICLES IN SOUND WAVES?

SVETLANKA909090 [29]

A vibrating string can create longitudinal waves as depicted in the animation below.

The answer is C) vibrations

8 0

3 years ago

If you had 15 molecules of H2 and an unlimited supply of N2, how many

Masja [62]

Answer:

10 molecules of NH₃.

Explanation:

N₂ + 3H₂ --> 2NH₃

As the N₂ supply is unlimited, what we need to do to solve this problem is convert molecules of H₂ into molecules of NH₃. To do so we use the stoichiometric coefficients of the balanced reaction:

15 molecules H₂ * $\frac{2moleculesNH_3}{3moleculesH_2}$ = 10 molecules NH₃

10 NH₃ molecules could be prepared from 15 molecules of H₂ and unlimited N₂.

8 0

3 years ago