The addition of hydrochloric acid to a silver nitrate solution precipitates silver chloride according to the reaction:
1 answer:
Answer:
Enthalpy change for the reaction is -67716 J/mol.
Explanation:
Number of moles of in 50.0 mL of 0.100 M of
= Number of moles of HCl in 50.0 mL of 0.100 M of HCl
= moles
= 0.00500 moles
According to balanced equation, 1 mol of reacts with 1 mol of HCl to form 1 mol of AgCl.
So, 0.00500 moles of react with 0.00500 moles of HCl to form 0.00500 moles of AgCl
Total volume of solution = (50.0+50.0) mL = 100.0 mL
So, mass of solution = () g = 100 g
Enthalpy change for the reaction = -(heat released during reaction)/(number of moles of AgCl formed)
=
=
= -67716 J/mol
[m = mass, c = specific heat capacity, = change in temperature and negative sign is included as it is an exothermic reaction]
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