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Gnoma [55]
3 years ago
13

CAN ANYONE ANSWER THIS ONE CHEMISTRY QUESTION PLZZZ!!!

Chemistry
2 answers:
xz_007 [3.2K]3 years ago
8 0

Answer:

2.8 oxygen

Explanation:

Pavlova-9 [17]3 years ago
4 0

Answer:

9.6, because 2.4 x 4 = 9.6 oxygen.

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What mass of oxalic acid dihydrate, H2C2O4•2H2O, is needed to make a 0.357 M solution of oxalic acid in a 250.0mL volumetric fla
GalinKa [24]

Molarity is expressed as the number of moles of solute per volume of the solution. The mass of oxalic acid dihydrate needed for the solution is calculated as follows:

Amount in moles: (0.357 mol H2C2O4•2H2O / L) (.250 L ) = 0.0893 mol H2C2O4•2H2O


Amount in mass : 0.0893 mol H2C2O4•2H2O (126.08 g / mol ) = 11.2589 g H2C2O4•2H2O


Hope this answers the question. Have a nice day.

5 0
3 years ago
5. How many atoms of hydrogen are in a molecule of acetic acid (HC2H202)?
Kazeer [188]

Answer:

in acetic acid ,there are 4 hydrogen atoms

Explanation:

C H 3 C O O H

3 0
3 years ago
In the titration of wine to determine the acid concentration, 10.0 mL of wine was placed in a beaker and diluted with 40.0 mL of
BARSIC [14]

Answer:

0.0042 M is the molarity of tartaric acid in this sample of wine.

Explanation:

To calculate the concentration of acid, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is tartaric acid

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is NaOH.

We are given:

n_1=2\\M_1=?\\V_1=10.0+40.0 mL=50.0 mL\\n_2=1\\M_2=0.051 M M\\V_2=8.20 mL

Putting values in above equation, we get:

2\times M_1\times 50.0 mL=1\times 0.051 M\times 8.20 mL

M_1=\frac{1\times 0.051 M\times 8.20 mL}{2\times 50.0 mL}=0.0042 M

0.0042 M is the molarity of tartaric acid in this sample of wine.

6 0
3 years ago
How many grams of Aluminum Oxide are produced when 3.64 g of Aluminum reacts with an excess of Oxygen?
fgiga [73]
55664 grams of aluminum oxide gag
4 0
3 years ago
Read 2 more answers
Which of the following is true about mixtures?
Hatshy [7]
The correct answer is D. Mixtures can be easily separated solutions cannot.
8 0
3 years ago
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