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3 years ago

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An alpha particle (a helium nucleus, consisting of two protons and two neutrons) has a radius of approximately 1.6 × 10-15 m. A

certain heavy nucleus contains 79 protons in addition to all its neutrons and has a radius of approximately 5.8 × 10-15 m. An alpha particle is shot directly from a large distance at such a resting heavy nucleus.
What is the initial momentum of the alpha particle?

1 answer:

Snezhnost [94]3 years ago

8 0

Answer:

9.96x10^-20 kg-m/s

Explanation:

Momentum p is the product of mass and velocity, i.e

P = mv

Alpha particles, like helium nuclei, have a net spin of zero. Due to the mechanism of their production in standard alpha radioactive decay, alpha particles generally have a kinetic energy of about 5 MeV, and a velocity in the vicinity of 5% the speed of light.

From this we calculate the speed as

v = 5% 0f 3x10^8 m/s (speed of light)

v = 1.5x10^7 m/s

The mass of an alpha particle is approximately 6.64×10−27 kg

Therefore,

P = 1.5x10^7 x 6.64×10^−27

P = 9.96x10^-20 kg-m/s

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vesna_86 [32]

Answer:

∴Inductance of solenoid A is $\frac18$ of inductance of solenoid B.

Explanation:

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$\frac {\textrm{Inductance of A}}{\textrm{Inductance of B}}=\frac{\mu_0\pi\frac{N^2D^2}{4L}}{\mu_0\pi\frac{16 N^2D^2}{4.2L}}$

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∴Inductance of solenoid A is $\frac18$ of inductance of solenoid B.

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