Answer:
(a) 0.0113 T
(b) 4.07 x 10^-4 Henry
(c) 0.02 Volt
Explanation:
number of turns, N = 360
length, l = 20 cm = 0.2 m
Area of crossection, A = 5 cm^2 = 5 x 10^-4 m^2
i = 5 A
(a) The formula for the magnetic field of the solenoid
where, B be the strength of magnetic field, n be the number of turns per unit length, i be the current in the solenoid and μo is the absolute permeability of free space.
So, n = N / l = 360 / 0.2 = 1800 per metre
So, magnetic field strength
B = 0.0113 T
(b) Let L be the self inductance of the solenoid
Where, N be the total number of turns, A be the area of crossection
L = 4.07 x 10^-4 Henry
(c) di / dt = 50 A/s
The relation between the electromotive force and the rate of change of current is given by
e = - 4.07 x 10^-4 x 50 = - 0.02 Volt
Negative sign shows the direction of electro motive force.