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solmaris [256]
3 years ago
13

When a pendulum is at the midpoint of its oscillation, hanging straight down, which statement is true?

Physics
2 answers:
Svetach [21]3 years ago
5 0
When a pendulum is at the midpoint of its oscillation, hanging straight down ...

-- that's the fastest it's going to swing, so its kinetic energy is maximum;
and
-- that's the lowest it's going to get, so its potential energy is minimum.

'c' is your choice.
Misha Larkins [42]3 years ago
3 0

c. Kinetic energy is maximum and potential energy is minimum.

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What is centripental force?
agasfer [191]

Answer:

Centripetal force is the force that is necessary to keep an object moving in a curved path and that is directed inward towards the center of rotation.

Explanation:

Definition of centripetal force:

Centripetal force is the force that is necessary to keep an object moving in a curved path and that is directed inward towards the center of rotation.

Example of centripetal force

A string on the end of which a stone is whirled about exerts a centripetal force on the stone.

The diagram is shown below

Where

The centripetal forces acting towards the centre C that is \vec {AC}

and the direction is from A to C.

And the stone is moving in a circular motion with center as C.

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The ratio of carbon-14 to nitrogen-14 in an artifact is 1:7. Given that the half-
ycow [4]

Answer:

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Explanation:

A p e x

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3 years ago
At a pressure of one atmosphere methane boils at −161°C and freezes at −182.5°C. Consider a temperature scale where the boiling
lawyer [7]

Answer:

-421.627906977\^{\circ}M

Explanation:

Absolute zero in the Kelvin scale = -273.15 °C

Temperature difference in the boiling and freezing point

-161-(-182.5)=21.5\ ^{\circ}C

Change in 21.5°C = Change of 100°C in M

1^{\circ}C=\dfrac{100}{21.5}=4.6511627907\ ^{\circ}M

Difference in the Celsius scale

-182.5-(-273.15)=90.65\ ^{\circ}C

Change in 90.65\ ^{\circ}C corresponds to

4.6511627907\times 90.65=421.627906977\ ^{\circ}M

Therefore the absolute zero in the Methane scale is

-421.627906977\ ^{\circ}M

3 0
3 years ago
A 5000kg car traveling at 40m/s crashes into a wall and comes to a complete stop in 10s. What was the force on the wall? solve s
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Answer:

20,000 N

Explanation:

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a = Δv / Δt

a = (0 − 40 m/s) / 10 s

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Next use Newton's second law to find the force on the car:

F = ma

F = (5000 kg) (-4 m/s²)

F = -20,000 N

According to Newton's third law, the force on the wall is equal and opposite the force on the car.

F = 20,000 N

4 0
3 years ago
Please help me!!!!!!!!!!!!!!!​
qaws [65]

Answer:

3

Explanation:

i did it

3 0
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