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3 years ago

When a pendulum is at the midpoint of its oscillation, hanging straight down, which statement is true?

2 answers:

5 0

When a pendulum is at the midpoint of its oscillation, hanging straight down ...

-- that's the fastest it's going to swing, so its kinetic energy is maximum;
and
-- that's the lowest it's going to get, so its potential energy is minimum.

'c' is your choice.

Misha Larkins [42]3 years ago

3 0

c. Kinetic energy is maximum and potential energy is minimum.

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A man with a weight of 100 N is located

valentina_108 [34]

Answer:

Given,

mass of man = 100 N = 10 kg

height = h = 25m

since the man does not move anything with his force, work done by him is zero

work done on the man = gain in potential energy

P.E=mgh

P.E=10×9.8×25

P.E=2.45KJ

Explanation:

so, potential energy gained by man is 2.45 KJ

5 0

2 years ago

a large parallel plate capacitor has plate seperation of 1.00 cm and plate area of 314 cm^2. The capacitor is connected across a

Whitepunk [10]

Answer:

$W = -2.76\times 10^{-9}~J$

Explanation:

The work done on the capacitor is equal to the difference in potential energy stored in the capacitor in two different cases.

The potential energy is given by the following formula:

$U = \frac{1}{2}CV^2$

where C can be calculated using the plate separation and area.

$C = \epsilon\frac{A}{d} = \epsilon\frac{0.0314}{0.01} = 3.14\epsilon$

Therefore, the potential energy in the first case is

$U = \frac{1}{2}3.14\epsilon (20)^2 = 628\epsilon$

In the second case:

$C_2 = \epsilon\frac{A}{d} = \epsilon\frac{0.0314}{0.02} = 1.57\epsilon\\U = \frac{1}{2}C_2 V^2 = \frac{1}{2}1.57\epsilon (20)^2 = 314\epsilon$

The permittivity of the air is very close to that of vacuum, which is 8.8 x 10^-12.

So, the difference in the potential energy is

$W = U_2 - U_1 = \epsilon(314 - 628) = -314 \times 8.8 \times 10^{-12} = -2.76\times 10^{-9}~J$

6 0

3 years ago

What is the cost of operating a 100 W light bulb for "4 hrs per day" for 30 days, if the cost of electricity is 6 cents kW•h

Sidana [21]

Answer:

the cost of operating the light bulb is 72 cents.

Explanation:

Given;

cost of electricity, C = 6 cents / kW.h

power of light bulb, P = 100 W

time of light power consumption, t = 4 hours per day for 30 days

total time = 4 hours x 30 = 120 hours

Power consumed by the light bulb is calculated as;

P = 100 x 120 = 12000 w.h = 12 kW.h

Cost of power consumption = 6 cents/kWh x 12 kWh

= 72 cents

Therefore, the cost of operating the light bulb is 72 cents.

3 0

3 years ago

An object moves in simple harmonic motion with amplitude 11m and period 4 minutes. At time t = 0 minutes, its displacement d fro

Sergio039 [100]

Answer:

Explanation:

Angular velocity ω = 2π / T = 2 x 3 . 14 / (4 x 60 ) = .026 rad / s.

d = D Sin ( ωt + θ ) where D = amplitude = 11 m θ = initial phase.

-11 = 11 sin ( 0 + θ ) = sin θ = -1 , θ = - π /2

So, d = D Sin ( ωt - θ )

d = 11 Sin ( .026 t - π /2 ) is the required equation.

8 0

3 years ago

Complete the statement about memory improvement.

Liula [17]

Elaborate rehearsal involves organizing and breaking down information into easier groups to expand capacity. Rehearsal is the verbal repetition of information. These techniques are especially important for the improvement of long-term memory.

Six strategies of elaborate rehearsal are:

1. Rephrase information into your own words.

2. Create your own study questions and answer them.

3. Use images to help you.

4. Group terms that are of the same topic together.

5. Use a mnemonic strategy.

6. Space our your learning and don't try to cram in on sitting.

8 0

2 years ago