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solmaris [256]
3 years ago
13

When a pendulum is at the midpoint of its oscillation, hanging straight down, which statement is true?

Physics
2 answers:
Svetach [21]3 years ago
5 0
When a pendulum is at the midpoint of its oscillation, hanging straight down ...

-- that's the fastest it's going to swing, so its kinetic energy is maximum;
and
-- that's the lowest it's going to get, so its potential energy is minimum.

'c' is your choice.
Misha Larkins [42]3 years ago
3 0

c. Kinetic energy is maximum and potential energy is minimum.

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A mass-spring system has k = 56.8 N/m and m = 0.46 kg.
andriy [413]

Answer:

A. \omega=11.1121\ rad.s^{-1}

B. f=1.7685\ Hz

C. T=0.5654\ s

Explanation:

Given:

  • spring constant, k=56.8\ N.m^{-1}
  • mass attached, m=0.46\ kg

A)

for a spring-mass system the frequency is given as:

\omega=\sqrt{\frac{k}{m} }

\omega=\sqrt{\frac{56.8}{0.46}}

\omega=11.1121\ rad.s^{-1}

B)

frequency is given as:

f=\frac{\omega}{2\pi}

f=\frac{11.1121}{2\pi}

f=1.7685\ Hz

C)

Time period of a simple harmonic motion is given as:

T=\frac{1}{f}

T=0.5654\ s

7 0
3 years ago
How much time does it take for a car to accelerate from 3.44 m/s to 20.9 m/s if the average acceleration is 6.00 m/s^3
miv72 [106K]

Do you go to GA Connexus Academy??

4 0
3 years ago
Read 2 more answers
If you lived by the sea, what effect of the moon would you see? Describe the effect.
dolphi86 [110]

Answer:

the changes in waves

Explanation:

the moon has its own gravitational pull thus making waves  and the rising tides

8 0
3 years ago
Use a(t) = -32 feet per second per second as the acceleration due to gravity. (Neglect air resistance.) -With what initial veloc
Kitty [74]

Answer:

u= 187.61 ft/s

Explanation:

Given that

g= - 32 ft/s²

The maximum height ,h= 550 ft

Lets take the initial velocity = u ft/s

We know that

v²=u² + 2 g s

v=final speed ,u=initial speed ,s=height

When the object reach at the maximum height then the final speed of the object will become zero.

That is why

u²= 2 x 32 x 550

u²= 35200

u= 187.61 ft/s

That is why the initial speed will be 187.61 ft/s

7 0
3 years ago
Read 2 more answers
What is time taken by the stone ?
SSSSS [86.1K]

The time taken by the stone to hit the ground would be 5.12 seconds.

<h3>What are the three equations of motion?</h3>

There are three equations of motion given by  Newton

The first equation is given as follows

v = u + at

the second equation is given as follows

S = ut + 1/2×a×t²

the third equation is given as follows

v² - u² = 2×a×s

Keep in mind that these calculations only apply to uniform acceleration.

As given in the problem, a stone is dropped from the helicopter which is ascending at the speed of 19.6 m/s

height(S) = 156.8 meters

initial velocity(u) = -19.6 m/s

acceleration(a) = 9.81 m/s²

By using the second equation of motion given by newton

S = ut + 1/2at²

S = 156.8m ,u= -19.6 m/s , a= 9.81 m/s² and t =? seconds

156.8= -19.6t + 9.81t²

t = 5.12 seconds

Thus, the time taken by the stone to hit the ground would be 5.12 seconds.

Learn more about equations of motion from here,

brainly.com/question/5955789

#SPJ1

8 0
1 year ago
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