Answer: There is 125 mL of a 2.0 M CuCl2 solution are needed to make 500 mL of a 0.5 M solution
Explanation:
Given:
= 2.0 M,
= ?
= 0.5 M,
= 500 mL
Formula used to calculate the volume is as follows.
![M_{1}V_{1} = M_{2}V_{2}](https://tex.z-dn.net/?f=M_%7B1%7DV_%7B1%7D%20%3D%20M_%7B2%7DV_%7B2%7D)
Substitute the values into above formula as follows.
![M_{1}V_{1} = M_{2}V_{2}\\2.0 M \times V_{1} = 0.5 M \times 500 mL\\V_{1} = 125 mL](https://tex.z-dn.net/?f=M_%7B1%7DV_%7B1%7D%20%3D%20M_%7B2%7DV_%7B2%7D%5C%5C2.0%20M%20%5Ctimes%20V_%7B1%7D%20%3D%200.5%20M%20%5Ctimes%20500%20mL%5C%5CV_%7B1%7D%20%3D%20125%20mL)
Thus, we can conclude that there is 125 mL of a 2.0 M
solution are needed to make 500 mL of a 0.5 M solution.
Answer:
.055 mol/L
Explanation:
Henry's Law is about solubility of a gas in a liquid which is dependent on the partial pressure of gas above the liquid . According to it
C = k P where C is concentration of gas in the liquid , k is henry's constant and P is partial pressure of the gas .
Given k = .159 mol/L.atm
P = 265 mm of Hg
= 265 / 760
= .34868 atm
C = kP
= .159 x .34868
= .055 mol/L
I think it is B for the answer
Answer:
c.O
Explanation:
From the periodic table:
Ionization energy tends to increase from IE6 → IE7 drastically at 13329 to 71345. Hence, from this process, we can infer that the removal of electrons takes place from the inner shell which in turn has a higher affinity for the nucleus. This must be oxygen because oxygen contains 6 valence electrons. The removal of this valence electron after the sixth ionization results in the achievement of a stable nearest Noble gas configuration. Hence, the rapid change in the ionization is obvious from IE6 to IE7.
Thus, the element that relates to the IE trend is oxygen.