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GarryVolchara [31]
3 years ago
8

Calculate the mass of water having same number of hydrogen atoms as are present in the 32gram of methane. Please help me soon...

...​
Chemistry
1 answer:
Ira Lisetskai [31]3 years ago
6 0

Answer:

Explanation:

1 mole of methane = C + H4 = 12 + 4 = 16

32 grams of methane is 32/16 = 2 moles.

1 moles of methane contains 4 moles of hydrogen (CH4). Note the 4 in CH4

2 moles of methane = 8 moles of hydrogen.

H2O has 2 moles of hydrogen

Each mole of water contains 2 moles of hydrogen.

8 moles of hydrogen / 2 moles = 4 moles of water.

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What is the total number of grams of mg consumed when 0.50 mole of h2 is produced
rosijanka [135]

Answer:

12 grams

<em>Please mark as Brainliest :)</em>

4 0
2 years ago
Molecule contains carbon, hydrogen and sulfur atoms. When a sample of 0.535g of this compound is burnt in oxygen, 1.119 g of CO2
OLga [1]

Answer:

The empirical formula is, C4H4S

Explanation:

Number of moles of carbon = 1.119 g/ 44g/mol = 0.025 moles

Mass of Carbon= 0.025 moles × 12 g/ mole = 0.3 g

Number of moles of hydrogen = 0.229/18g/mol × 2 = 0.025 moles

Mass of hydrogen = 0.025 moles × 1 = 0.025 g

Number of moles of sulphur = 0.407g/ 64 g/mol = 0.0064 moles

Mass of sulphur= 0.0064 moles ×32 = 0.2 g

Now we obtain the mole ratios by dividing through by the lowest ratio.

C- 0.025 moles/ 0.0064 moles, H- 0.025 moles/ 0.0064 moles, S- 0.0064 moles/0.0064 moles

C4H4S

4 0
3 years ago
How do countries with different currencies trade goods with each other?
8090 [49]

Answer:

D- They use the exchange rate to convert one's Country's currency to another's

Explanation:

6 0
3 years ago
The compound dioxane, which is used as a solvent in various industrial processes is composed of C,H, and O atoms. Combustion of
Lady_Fox [76]

Answer:

The correct formula of dioxane is C₄H₈O₂.

Explanation:

Given data:

mass of dioxane= 2.23 g

mass of water = 1.802 g

mass of carbon dioxide = 4.401 g

molar mass of dioxane = 88.1 g / mol

Molecular formula of dioxane = ?

Solution:

percentage of carbon = (4.401 g/2.23 g ) × (12 /44) × 100

                                     =  (1.98 × 0.273) × 100 = 54.1

percentage of hydrogen =  (1.802 g/ 2.23 g) × (2.016 /18.016) × 100

                                         = (0.81 × 0.112) × 100 = 9.072

percentage of oxygen = 100 - (54.1 + 9.072)

                                     = 100 - 63.172 = 36.828

Now we will determine the number of grams atoms of carbon, hydrogen and oxygen.

No. of gram atoms of carbon = 54.1 /12 = 4.51

No. of gram atoms of hydrogen = 9.072 / 1.008 = 9

No. of gram atoms of oxygen = 36.828 / 16 = 2.302

Atomic ratio:

    C :H :O               4.51/ 2.302    :   9 / 2.302   :  2.302 /2.302

    C :H :O                2 : 4 : 1

Molecular formula:

   Molecular formula = n × (empirical formula)

   n = molar mass of compound / empirical formula mass

   empirical formula mass= 2 × 12 + 4 × 1.008  + 1 × 16

    empirical formula mass= 24+ 4.032 +16 = 44.032

                 n = 88.1 / 44.032 = 2

        Molecular formula = n × (empirical formula)

        Molecular formula = 2 × (C₂H₄O)

         Molecular formula = C₄H₈O₂

8 0
3 years ago
Does a large ball of aluminum foil have the same properties as a small ball?
dsp73

Answer:

yes

Explanation:

same properties different size

can i have brainliest pls

5 0
3 years ago
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