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GarryVolchara [31]
3 years ago
8

Calculate the mass of water having same number of hydrogen atoms as are present in the 32gram of methane. Please help me soon...

...​
Chemistry
1 answer:
Ira Lisetskai [31]3 years ago
6 0

Answer:

Explanation:

1 mole of methane = C + H4 = 12 + 4 = 16

32 grams of methane is 32/16 = 2 moles.

1 moles of methane contains 4 moles of hydrogen (CH4). Note the 4 in CH4

2 moles of methane = 8 moles of hydrogen.

H2O has 2 moles of hydrogen

Each mole of water contains 2 moles of hydrogen.

8 moles of hydrogen / 2 moles = 4 moles of water.

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Help. The answer to question 1 I didn't mean to click so please answer that as well.
Zepler [3.9K]
We have that energy=specific heat * change in temperature * mass. Thus, we have the final temperature (22) minus the initial temperature (55) to equal -33 as our change in temperature. Our specific heat is in J/g*C, so we're good with that because g stands for grams and the aluminium is measured in grams. As there are 10 grams of aluminum, we have
10*(-33)*0.902=-298 ish as our final temperature

An exothermic reaction would release energy and would therefore lose heat itself, while an endothermic reaction would absorb energy and gain heat. Therefore, losing heat would be an exothermic reaction

Feel free to ask further questions!
4 0
3 years ago
Which salt is formed by the reaction between hydrochloric acid and sodium hydroxide, write with chemical equation. .​
stepan [7]

Answer:

salt sodium chloride (NaCl)

8 0
3 years ago
What is the smallest division on this balance?
sesenic [268]
0.001 would be the smallest.

Good Luck! :)
4 0
4 years ago
Read 2 more answers
Lead(II) nitrate and ammonium iodide react to form lead(II) iodide and ammonium nitrate according to the reaction Pb(NO3)2(aq)+2
Setler79 [48]

Answer:

a) volume of ammonium iodide required =349 mL

b) the moles of lead iodide formed = 0.0436 mol

Explanation:

The reaction is:

Pb(NO_{3})_{2}+2NH_{4}I -->PbI_{2}+2NH_{4}NO_{3}

It shows that one mole of lead nitrate will react with two moles of ammonium iodide to give one mole of lead iodide.

Let us calculate the moles of lead nitrate taken in the solution.

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Moles of lead nitrate = 0.360 X 0.121 =0.0436 mol

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volume=\frac{moles}{molarity}=\frac{0.0872}{0.250}=0.349L=349mL

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7 0
3 years ago
Which system is not directly connected to itself
Nataliya [291]

Answer:

B) Digestive

Explanation:

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5 0
3 years ago
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