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GarryVolchara [31]
3 years ago
8

Calculate the mass of water having same number of hydrogen atoms as are present in the 32gram of methane. Please help me soon...

...​
Chemistry
1 answer:
Ira Lisetskai [31]3 years ago
6 0

Answer:

Explanation:

1 mole of methane = C + H4 = 12 + 4 = 16

32 grams of methane is 32/16 = 2 moles.

1 moles of methane contains 4 moles of hydrogen (CH4). Note the 4 in CH4

2 moles of methane = 8 moles of hydrogen.

H2O has 2 moles of hydrogen

Each mole of water contains 2 moles of hydrogen.

8 moles of hydrogen / 2 moles = 4 moles of water.

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A bond formed between a fluorine, F, atom and a fluorine, F, atom is likely to be____
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c) non polar Covalent

Explanation:

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3 years ago
Find the percentage composition of each element in the compound having 9.8 grams of nitrogen,0.7 grams of hydrogen and 33.6 gram
prisoha [69]

Answer: The percentage composition of nitrogen , hydrogen and oxygen is 22.2 % , 1.59 % and 76.2% respectively.

Explanation:

Percentage composition is defined as the ratio of mass of substance to the total mass in terms of percentage.

Percentage composition=\frac{\text {mass of the element}}{\text {Total mass of the substance}}\times 100\%

a) {\text {percentage composition of nitrogen}}=\frac{\text {mass of nitrogen}}{\text {Total mass}}\times 100\%

{\text {percentage composition of nitrogen}}=\frac{9.8g}{9.8+0.7+33.6}\times 100\%=22.2\%

b) {\text {percentage composition of hydrogen}}=\frac{\text {mass of hydrogen}}{\text {Total mass}}\times 100\%

{\text {percentage composition of hydrogen}}=\frac{0.7}{9.8+0.7+33.6}\times 100\%=1.59\%

c) {\text {percentage composition of oxygen}}=\frac{\text {mass of oxygen}}{\text {Total mass}}\times 100\%

{\text {percentage composition of oxygen}}=\frac{33.6}{9.8+0.7+33.6}\times 100\%=76.2\%

The percentage composition of nitrogen , hydrogen and oxygen is 22.2 % , 1.59 % and 76.2% respectively.

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3 years ago
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C




I’m pretty sure it’s c
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3 years ago
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