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GarryVolchara [31]
3 years ago
8

Calculate the mass of water having same number of hydrogen atoms as are present in the 32gram of methane. Please help me soon...

...​
Chemistry
1 answer:
Ira Lisetskai [31]3 years ago
6 0

Answer:

Explanation:

1 mole of methane = C + H4 = 12 + 4 = 16

32 grams of methane is 32/16 = 2 moles.

1 moles of methane contains 4 moles of hydrogen (CH4). Note the 4 in CH4

2 moles of methane = 8 moles of hydrogen.

H2O has 2 moles of hydrogen

Each mole of water contains 2 moles of hydrogen.

8 moles of hydrogen / 2 moles = 4 moles of water.

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In liquids, the attractive intermolecular forces are ________. In liquids, the attractive intermolecular forces are ________. st
Fantom [35]

Answer:

strong enough to hold molecules relatively close together but not strong enough to keep molecules from moving past each other.

Explanation:

In liquids, the attractive intermolecular forces are <u>strong enough to hold molecules relatively close together but not strong enough to keep molecules from moving past each other</u>.

Intermolecular forces are the forces of repulsion or attraction.

Intermolecular forces lie between atoms, molecules, or ions. Intramolecular forces are strong in comparison to these forces.

<u />

5 0
3 years ago
What is a scientific law?
Stells [14]

Answer:

Scientific laws or laws of science are statements, based on repeated experiments or observations, that describe or predict a range of natural phenomena. The term law has diverse usage in many cases across all fields of natural science.

Explanation:

I hope this helps

3 0
3 years ago
Read 2 more answers
The element copper has 29 protons. What is the atomic number of copper?
stiks02 [169]
The atomic number of copper is 29.

Hope this helps and if it does, don't be afraid to rate my answer as well as maybe give it a "Thanks"? (Or even better a "Brainliest"). And if it’s not correct, I am sorry for wasting your time, and good luck finding the correct answer :)


8 0
3 years ago
Read 2 more answers
Pu is a nuclear waste byproduct with a half-life of 24,000 y. What fraction of the 239Pu present today will be present in 1000 y
olya-2409 [2.1K]

Answer:

0.9715 Fraction of Pu-239 will be remain after 1000 years.

Explanation:

\lambda =\frac{0.693}{t_{\frac{1}{2}}}

A=A_o\times e^{-\lambda t}

Where:

\lambda= decay constant

A_o =concentration left after time t

t_{\frac{1}{2}} = Half life of the sample

Half life of Pu-239 = t_{\frac{1}{2}}=24,000 y[

\lambda =\frac{0.693}{24,000 y}=2.8875\times 10^{-5} y^{-1]

Let us say amount present of  Pu-239 today = A_o=x

A = ?

A=x\times e^{-2.8875\times 10^{-5} y^{-1]\times 1000 y}

A=0.9715\times x

\frac{A}{A_0}=\frac{A}{x}=0.9715

0.9715 Fraction of Pu-239 will be remain after 1000 years.

7 0
3 years ago
Differentiate between Acidic radical and basic radical ​
Paladinen [302]

Explanation:

<em>Acidic</em><em> </em><em>radical</em><em> </em>

<em>Acid radical is the ion formed after the removal of Hydrogen ion (H+) from an acid. Example: When H2SO4 loses H+ ion, it forms HSO4− which is an acid radical.</em><em> </em>

<em>Basic</em><em> </em><em>radical</em><em> </em>

<em> The ion formed after the removal of hydroxide ion (OH−) from a base is known as basic radical.</em>

3 0
3 years ago
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