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Lady bird [3.3K]
3 years ago
13

A hot air balloon is rising vertically with a velocity of 10.0 feet per second. A very small ball is released from the hot air b

alloon at the instant when it is 960 feet above the ground. Use a(t)=−32 ft/sec2 as the acceleration due to gravity.
1. How many seconds after its release will the ball strike the ground? Round the answer to the nearest two decimal places.

2. At what velocity will it hit the ground?
Physics
1 answer:
krek1111 [17]3 years ago
7 0

Answer:

Explanation:

Given that,

The rising velocity of the balloon

U = 10 ft/s

The height where a small balloon is release is

y = 960ft

Taking g = - 32 ft/s²

A. Time the balloon will strike the ground.

Using the equation of free fall

∆y = ut + ½gt².

0—960 = 10t + ½× -32 × t²

- 960 = 10t —16t²

16t² — 10t — 960 = 0

Divide through by 2

8t²—5t —480= 0

Using quadratic formula method

t = [-b ± √(b²-4ac)] / 2a

a = 8 b = -5 and c = -480

t = [--5 ± √((-5)²-4×8×-480)] / 2×8

t = [5 ± √(25+15360)] / 16

t = [5 ± 124.04] / 16

Let discard the negative time since time can't be negate

Then, t = [5+124.06] / 16

t = 8.065 seconds

To 2d.p

t = 8.06 seconds

B. Final velocity it hits the ground

Using equation of motion.

V = U + gt

V = 10 + (-32) × 8.06

V = 10 — 258.07

V = —248.07m/s

The negative sign is showing that it is moving downward

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Answer:

(a) The ratio of turns in the primary and secondary coils of her transformer is 1.833

(b) The ratio of input to output current is 0.55

(c) To increase the output voltage, you can either increase the number of turns in the secondary coil (step-up) or increase the input current. Therefore, the Chinese person has to increase the input current of the transformer to achieve an increased output voltage that can power her 220 V appliances.

Explanation:

Given;

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output voltage, V_s = 120 V

General transformer equation is given as;

\frac{V_p}{V_s} = \frac{N_p}{N_s} = \frac{I_s}{I_p}

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Ns is number of turns in the secondary coil

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Ip - is the primary current or input current

(a) The ratio of turns in the primary and secondary coils of her transformer;

\frac{N_p}{N_s} = \frac{V_p}{V_s} \\\\\frac{N_p}{N_s} = \frac{220}{120} = 1.833

(b) The ratio of input to output current;

\frac{I_p}{I_s} = \frac{V_s}{V_p} \\\\\frac{I_p}{I_s} = \frac{120}{220} \\\\\frac{I_p}{I_s} = 0.55

(c) To increase the output voltage, you can either increase the number of turns in the secondary coil (step-up) or increase the input current. Therefore, the Chinese person has to increase the input current of the transformer to achieve an increased output voltage that can power her 220 V appliances.

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Young’s modulus is property of gas
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Explanation:

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Imagine a particular exoplanet covered in an ocean of liquid methane. At the surface of the ocean, the acceleration of gravity i
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Answer:

Explanation:

Atmospheric pressure = 7 x 10⁴ Pa

force on  a disk-shaped region 2.00 m in radius at the surface of the ocean due to atmosphere  = pressure x area

= 7 x 10⁴ x 3.14 x 2 x 2

= 87.92 x 10⁴ N

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= 10 x 415 x 6.2 x 3.14 x 2 x 2

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= 7 x 10⁴ + 10 x 415 x 6.2 ( hρg)

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A pogo stick has a spring with a force constant of 2.50 × 104 N/m , which can be compressed 11.2 cm. what maximum height, in met
AleksandrR [38]

Answer:

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given,

spring constant = 2.5 x 10⁴ N/m

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\dfrac{1}{2}kx^2 = mgh

\dfrac{1}{2}\times 2.5 \times 10^4 \times 0.112^2 = 44\times 9.8 \times h

\dfrac{1}{2}\times 2.5 \times 10^4 \times 0.112^2 = 44\times 9.8 \times h

156.8 = 44 \times 9.8 \times h

h = \dfrac{156.8}{44 \times 9.8}

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Answer:

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Explanation:

In the answer.

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