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polet [3.4K]
2 years ago
13

What location on earth that is directly hit by the light during a summer solstice?

Physics
1 answer:
jenyasd209 [6]2 years ago
7 0

Answer:

Solstice usually refers to the condition when there occurs the longest duration of day and night and during this time the north pole of the earth is tilted at the farthest distance from the location of the sun. There are two types of the solstice, namely the summer and the winter solstice.

In the case of the northern hemisphere or the upper half of the equator, the summer solstice usually occurs in June 21st and the winter solstice occurs in December 21st.

The locations on earth where the sunlight is directly incident during the time of summer solstice are the regions lying in the tropic of cancer namely, India, Mexico, the southern portion of China and the Bahamas.

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What is the potential energy of a 5kg rock that is 7m high on a hill
Goryan [66]

Explanation:

Gravitational potential energy = mgh = (5)(9.81)(7) = 343.35J.

4 0
2 years ago
If you weigh 690 N on the earth, what would be your weight on the surface of a neutron star that has the same mass as our sun an
lana [24]

Answer:

Explanation:

Given that,

Mass of star M(star) = 1.99×10^30kg

Gravitational constant G

G = 6.67×10^−11 N⋅m²/kg²

Diameter d = 25km

d = 25,000m

R = d/2 = 25,000/2

R = 12,500m

Weight w = 690N

Then, the person mass which is constant can be determined using

W =mg

m = W/g

m = 690/9.81

m = 70.34kg

The acceleration due to gravity on the surface of the neutron star is can be determined using

g(star) = GM(star)/R²

g(star) = 6.67×10^-11 × 1.99×10^30 / 12500²

g (star) = 8.49 × 10¹¹ m/s²

Then, the person weight on neutron star is

W = mg

Mass is constant, m = 70.34kg

W = 70.34 × 8.49 × 10¹¹

W = 5.98 × 10¹³ N

The weight of the person on neutron star is 5.98 × 10¹³ N

5 0
3 years ago
Is it possible to calculate the displacement based on an elapsed time from a position time graph?
Nataly [62]
No I don’t think so. But it worth a try tho. Try it out.
5 0
3 years ago
Two blocks are connected by a light weight, flexible cord that passes over a frictionless pulley.Ifm1=2 kg and m2 = 3 kg, and bl
Vera_Pavlovna [14]

Answer:

t = 1.41 sec.

Explanation:

If we assume that the acceleration of the blocks is constant, we can apply any of the kinematic equations to get the time since the block 2 was released till it reached the floor.

First, we need to find the value of  acceleration, which is the same for both blocks.

If we take as our system both blocks, and think about the pulley as redirecting the force simply (as tension in the strings behave like internal forces) , we can apply Newton's 2nd Law, as they were moving along the same axis, aiming at opposite directions, as follows:

F = m₂*g - m₁*g = (m₁+m₂)*a (we choose as positive the direction of the acceleration, will be the one defined by the larger mass, in this case m₂)

⇒ a = (\frac{(m₂-m₁)}({m₁+m₂} * g = g/5 m/s²

Once we got the value of a, we can use for instance this kinematic equation, and solve for t:

Δx = 1/2*a*t² ⇒ t² = (2* 1.96m *5)/g = 2 sec² ⇒ t = √2 = 1.41 sec.

6 0
3 years ago
BEST ANSWER GETS MARKED AS BRAINLIEST!!!! Can someone PLZ help me come up with a study method, no matter what I try, I just can'
Leni [432]
For physics, I would recommend to just keep doing practice problems and reviewing notes. Repetition of the same concepts will help drill it into your brain. Hope that helps!
8 0
3 years ago
Read 2 more answers
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