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guapka [62]
3 years ago
8

In order to catch a fast-moving softball with your bare hand, you extend your hand forward just before the catch and then let th

e ball ride backward with your hand. doing this reduces the catching force because the
Physics
1 answer:
hichkok12 [17]3 years ago
8 0
This is a concept of momentum. In equation, momentum is the product of force and distance. When a ball is thrown, its force is constant all throughout unless disturbed by an external force. Therefore, force is the constant of proportionality that relates momentum with distance. When you block a ball from a given distance, you would feel the great force on your hand. In order to reduce the force, you have to follow the direction of the force in order to minimize the impact. By doing this, you gradually decrease the momentum of the ball. 
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Bob is studying waves in science and learns that the energy of a wave is directly proportional to the square of the waves amplit
Mrrafil [7]
For a simple harmonic motion energy is given with:
E=\frac{1}{2}kA^2
Where k is a constant that depends on the type of the wave you are looking at and A is amplitude.
Let's calculate the energy of the wave using two different amplitudes given in the problem:
E_1=\frac{1}{2}k(1)^2=\frac{1}{2}k\\E_2=\frac{1}{2}k(2)^2=\frac{4}{2}k=2k\\
We can see that energy associated with the wave is 4 times smaller when we decrease its amplitude by half. So the answer should be C.


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3 years ago
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When is orange is the new black episodes come out
xenn [34]
Some are out but will be on Netflix June 17
3 0
3 years ago
A squirrel jumps into the air with a velocity of 7 m/s at an angle of 20 degrees. What is the maximum height reached by the squi
Marina CMI [18]

Answer:

.3m

Explanation:

Apex

7 0
3 years ago
The work of energy theorem states that an increase in net work results in what?
Veseljchak [2.6K]
It results change only in it's kinetic energy, it's KE will increase in accord with the work-energy theorem 
3 0
3 years ago
. During a collision with a wall, the velocity of a 0.200-kg ball changes from 20.0 m/s toward the wall to 12.0 m/s away from th
mixer [17]

Answer:

106.7 N

Explanation:

We can solve the problem by using the impulse theorem, which states that the product between the average force applied and the duration of the collision is equal to the change in momentum of the object:

F \Delta t = m (v-u)

where

F is the average force

\Delta t is the duration of the collision

m is the mass of the ball

v is the final velocity

u is the initial velocity

In this problem:

m = 0.200 kg

u = 20.0 m/s

v = -12.0 m/s

\Delta t = 60.0 ms = 0.06 s

Solving for F,

F=\frac{m(v-u)}{\Delta t}=\frac{(0.200 kg) (-12.0 m/s-20.0 m/s)}{0.06 s}=-106.7 N

And since we are interested in the magnitude only,

F = 106.7 N

5 0
3 years ago
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