Question

If the magnitude of F1 is greater than the magnitude of F2, then the box is

Answer 1

Answer:

Moving at constant speed in the direction of $F_1$.

Explanation:

Let us consider that there are two forces acting on the box i.e $F_1\ and\ F_2$

Let us assume that $F_1$ is acting towards left and $F_2$ is acting towards right side. We know that force is a vector quantity.

If the magnitude of $F_1$ is than the magnitude of $F_2$, then the forces are unbalanced. Thus the box will move at constant speed in the direction of $F_1$.

Hence, the correct option is (B).

Answer 2

Assuming that the vectors are acting along the same axis, we could just simply add or subtract the vectors. Since the F1 is greater than F2, there would be motion, there would be acceleration, and that the direction of motion is along the F1.