If the magnitude of F1 is greater than the magnitude of F2, then the box is
2 answers:
Answer:
Moving at constant speed in the direction of .
Explanation:
Let us consider that there are two forces acting on the box i.e
Let us assume that is acting towards left and
is acting towards right side. We know that force is a vector quantity.
If the magnitude of is than the magnitude of
, then the forces are unbalanced. Thus the box will move at constant speed in the direction of
.
Hence, the correct option is (B).
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Answer:
a) the magnitude of the force is
F= Q() and where k = 1/4πε₀
F = Qqs/4πε₀r³
b) the magnitude of the torque on the dipole
τ = Qqs/4πε₀r²
Explanation:
from coulomb's law
E =
where k = 1/4πε₀
the expression of the electric field due to dipole at a distance r is
E(r) = , where p = q × s
E(r) = where r>>s
a) find the magnitude of force due to the dipole
F=QE
F= Q()
where k = 1/4πε₀
F = Qqs/4πε₀r³
b) b) magnitude of the torque(τ) on the dipole is dependent on the perpendicular forces
τ = F sinθ × s
θ = 90°
note: sin90° = 1
τ = F × r
recall F = Qqs/4πε₀r³
∴ τ = (Qqs/4πε₀r³) × r
τ = Qqs/4πε₀r²