If Neptune’s mass were reduced, what could be done to maintain the same force of gravitational attraction between Neptune and th
1 answer:
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Answer:
It traveled 4 centimeters.
Explanation:
In a speed versus time graph, the distance travelled is given by the area under the graph.
In this graph we have the following:
- The speed of the object is v = 1 cm/s between time t = 0 s and t = 4 s
- The speed of the object is v = 0 cm/s between time t = 4 s and t = 8 s
Since the speed in the second part is zero, the distance travelled in the second part is zero. So, the only distance travelled by the object is the distance travelled during the first part, which is equal to the area of the first rectangle:
Answer:
Explanation:
Here we know that for the given system of charge we have no loss of energy as there is no friction force on it
So we will have
now we know when particle will reach the closest distance then due to electrostatic repulsion the speed will become zero.
So we have
so distance moved by the particle is given as