<h3><u>Answer;</u></h3>
a) 5.00 x 10^8 J
<h3><u>Explanation;</u></h3>
The work done to move the sailboat is calculated through the equation;
W = F x d
where F is force and d is the distance.
Substituting the known values from the given above,
W = (5.00 x 10⁴ N)(10 km)(1000 m/ 1km)
= 5.00 x 10⁸ J
Thus, the work done is <u>5.00 x 10⁸Joules</u>
According to the condensation theory, the most important factor for the formation of our planets was "the interstellar dust attracting heat away from the protosun".
Condensation is the procedure by which water particles noticeable all around bunch together and shape fluid water. This is regularly observed outwardly of cold glasses. This idea additionally identifies with the solar system.
The condensation theory of the solar system expresses that our solar system, and perhaps all other galaxies, were shaped from a cloud of residue and gas that consolidated into strong issue. Space experts trust that the littlest grains of residue in our cloud applied a draw on the gas about it, 'consolidating' into bigger and bigger bits of issue, similarly as a snowball moving downhill will become bigger and bigger. In the long run, the gravitational draw of these residue atoms was sufficiently solid that they started to pull in each other, developing into greater and greater clusters that had more grounded gravitational pulls. In the long run, these bunches of residue and gas from the cloud frame a star, and potentially planets, space rocks, and comets turning about the star.
Answer:
1.6 x 10^-5 T
Explanation:
i = 4 A
r = 0.05 m
The magnetic field due to long wire at a distance r is given by
B = 10^-7 x 2 x 4 / 0.05
B = 1.6 x 10^-5 T
For this, you need the v-squared equation, which is v(final)² = v(initial)² + 2aΔx
The averate acceleration is thus a = (v(final)² - v(initial)²) / 2Δx = (20² - 15²) / 2(50) = 175 / 100 = 1.75 m/s²
So the average acceleration is 1.75 m/s²
This group is called “noble gases” because they do not react with other elements. This is because they have a full valence shell.