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Delvig [45]
3 years ago
13

g How many diffraction maxima are contained in a region of the Fraunhofer single-slit pattern, subtending an angle of 2.12°, for

a slit width of 0.110 mm, using light of wavelength 582 nm?
Physics
1 answer:
lbvjy [14]3 years ago
4 0

Answer:

2

Explanation:

We know that in the Fraunhofer single-slit pattern,

maxima is given by

a\text{sin}\theta=\frac{2N+1}{2}\lambda

Given values

θ=2.12°

slit width a= 0.110 mm.

wavelength λ= 582 nm

Now plugging values to calculate N we get

0.110\times10^{-3}\text{sin}2.12=(\frac{2N+1}{2})582\times10^{-9}

Solving the above equation we get

we N= 2.313≅ 2

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Suppose that the current in the solenoid is i(t). The self-inductance L is related to the self-induced EMF E(t) by the equation
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L =   μ₀ n r / 2I

Explanation:

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        E_{L} = - L dI / dt

 

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we can remove the differentials

      n Ф_B = L I

magnetic flux is defined by

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in this case the direction of the magnetic field is along the coil and the normal direction to the area as well, therefore the scalar product is reduced to the algebraic product

      n B A = L I

the loop area is

      A = π R²

     

we substitute

       n B π R² = L I                    (1)

To find the magnetic field in the coil let's use Ampere's law

        ∫ B. ds = μ₀ I

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we solve

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              B =  μ₀ I / 2πR

we substitute in

       n ( μ₀ I / 2πR) π R² = L I

       n  μ₀ R / 2 = L I

       L =   μ₀ n r / 2I

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