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malfutka [58]
3 years ago
10

Is the movement of plates to form land masses is called plate tectonics

Chemistry
1 answer:
joja [24]3 years ago
4 0
Yes the movement of land forms is called the movment of plate tectonics. :) plz thnk me
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Jessica wants to go for a run at the park. She usually runs about 8 kilometers per hour (km/h). She has about 1.5 hours to go fo
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c

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Which refers specifically to a heated solution that holds more dissolved solution than it can hold at a lower temperature?.
Westkost [7]

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Supersaturated solution

Explanation:

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Anyways, the best I can think of right now is a supersaturated solution.

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In metallic bonds, electrons are referred to as electrons.​
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Metallic bonding may be described as the sharing of free electrons among a lattice of positively charged metal ions. The structure of metallic bonds is very different from that of covalent and ionic bonds. ... In metallic bonds, the valence electrons from the s and p orbitals of the interacting metal atoms delocalize.

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3 years ago
The Top Thrill Dragster, a rollercoaster at Cedar Point in Ohio, soars through the air at 176ft/sec. How fast is this in mph?​
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7 0
2 years ago
Muscle physiologists study the accumulation of lactic acid [ch3ch(oh)cooh] during exercise. food chemists study its occurrence i
Drupady [299]
The provided information are:
volume of 0.85 M lactic acid = 225 ml
volume of 0.68 M sodium lactate = 435 ml
Ka of the lactate buffer = 1.38 x 10⁻⁴
 The equation for dissociation of lactic acid is:
CH₃CH(OH)COOH(aq) + H₂O ⇄ CH₃CH(OH)COO⁻(aq) + H₃O⁺(aq)
The pH of buffer is calculated from Henderson-Hasselbalch equation, which is:
pH = pKa + log \frac{[conjugated base]}{[Acid]}
pKa = - log Ka = - log (1.38 x 10⁻⁴) = 3.86 
The number of moles of lactic acid and lactate are as follows:
n (Lactic acid) = 225 ml x 0.85 mmol/ml = 191.25 mmol
n (Lactate) = 435 ml x 0.68 mmol/ml = 295.8 mmol
The number of moles of lactic acid and lactate in total volume of the solution:
[CH₃CH(OH)COOH] = n (lactic acid) / 660 ml = 191.25 mmol / 660 ml = 0.29 M
[CH₃CH(OH)COO⁻] = n (lactate) / 660 ml = 0.45 M
pH = 3.86 + log \frac{0.45 M}{0.29 M} = 3.86 + 0.191 = 4.05
So the pH of given solution is 4.05
7 0
3 years ago
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