Hydrogen atoms one outer electron so would be placed in group 1. However all group 1 elements are metals and elements in the same group have similar properties. Hydrogen is a non-metal and does not behave in the same way as the other group 1 elements, so that is why it is on its own.
Answer:
Q = 5350.2 Joules.
Explanation:
<u>Given the following data;</u>
Mass, m = 26. 5g
Initial temperature, T1 = 0°C
Final temperature, T2 = 48.3°C
Specific heat capacity of water, c = 4.18 J/g°C.
*To find the quantity of heat*
Heat capacity is given by the formula;
Where;
- Q represents the heat capacity or quantity of heat.
- m represents the mass of an object.
- c represents the specific heat capacity of water.
- dt represents the change in temperature.
dt = T2 - T1
dt = 48.3 - 0
dt = 48.3°C
Substituting the values into the equation, we have;
Q = 5350.2 Joules.
Therefore, the amount of heat absorbed is 5350.2 Joules.
The correct answer is : <span>Neon is inert because its outermost shell is complete.
Ne atomic number is 10 and has an electronic configuration of 1s</span>² 2s² 2p⁶.The outer shell is complete therefore Ne is inert, in other words inactive as its very stable with a complete outer shell.
Nitrogen is not inert as its atomic number is 7 and electronic configuration is 1s² 2s² 2p³. therefore valence electrons are 5, it needs 3 more electrons to gain the complete outer shell configuration. Therefore this statement is incorrect.
F has 7 valence electrons and needs only one more electron to complete its outer shell whereas O has 6 valence electrons and needs 2 electrons to complete its outer shell. Since F only needs one electron and O needs two electrons, F is more reactive than O therefore third statement is incorrect
F is more reactive than Ne as Ne is inert, however F needs to gain one electron and not lose, to fill its outermost shell therefore this statement too is incorrect
Answer:
AuCl
Explanation:
The solubility product constant, ksp, is defined as:
MₓYₙ(s) ⇄ xMⁿ⁺(aq) + nYˣ⁻(aq)
ksp = [Mⁿ⁺]ˣ + [Yˣ⁻]ⁿ
Thus, the higher ksp, the more soluble the compound is. Thus, the lower ksp the less soluble the compound is precipitating first. As the lower ksp is for Au, the first compound in precipitate is <em>AuCl</em>
I hope it helps!
What you are looking for is something from the left side of the periodic table (the metals), combined with something from the right side of the periodic table.
SiCl4 is something from the middle with something on the right. Not the answer.
HCl is a possible answer, but it is not the best one, because Hydrogen can be on both sides. It is not quite as willing to give up its electrons as the answer.
CCl4 has the same problem as A.
The answer is C
Ca is in column 2 just about as far left as you can get.
Cl is in column 17 which is just about as far right as you can get.