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abruzzese [7]
3 years ago
10

_______ are organic compounds containing a C=O bond, having strong aromas, and known for being volatile. A. Carboxylic acids B.

Amines C. Ethers D. Esters
Chemistry
2 answers:
stellarik [79]3 years ago
8 0
The answer is D.esters...only esters has a smell
rusak2 [61]3 years ago
6 0
Both carboxylic acids and esters are organic compounds with C=O bonds, however carboxylic acids contain very polar O-H groups which can hydrogen bond while esters do not. Therefore carboxylic acids have generally relatively high boiling points and are therefore not very volatile, while esters are. Additionally, esters tend to have strong aromas, and are used in many flavoured and scented products, while carboxylic acids are not. So the answer is D, esters.
Hope this helps!
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A metal X from two oxide A and B .3.oogm of A and B contain 0.72 and 1.16g of oxygen respectively.calculate the maases of metal
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Answer:

Explanation:

Firstly, we have to determine the mass of metal X. We can do that by interpreting the first and second statement mathematically.

Metal X can form 2 oxides (A and B).

A + B = 3g

The mass of oxygen in A is 0.72g and the mass of oxygen in B is 1.16g.

The mass of metal X in the two oxides will be the same because it's the same metal.

Thus, we represent the mass of the metal in the two oxides as 2X.

2X + 0.72 + 1.16 = 3

2X + 1.88 = 3

2X = 3 - 1.88

2X = 1.12

X = 0.56

<u>Thus, 0.56 g of the metal combines with 0.72g of oxygen in A and 1.16 g of oxygen in B.</u>

Thus, mass of metal (X) in 1g of oxygen in A is

0.56g ⇒ 0.72g

X ⇒ 1

X = 1 × 0.56/0.72

X = 0.78 g

Hence, 0.78g of the metal will combine with 1g of oxygen for A

Also, mass of metal (X) in 1g of oxygen in B is

0.56g ⇒ 1.16g

X ⇒ 1g

X = 1×0.56/1.16

X = 0.48 g

Thus, 0.48g of the metal will combine with 1g of oxygen for B

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Answer:

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Explanation:

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