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abruzzese [7]
3 years ago
10

_______ are organic compounds containing a C=O bond, having strong aromas, and known for being volatile. A. Carboxylic acids B.

Amines C. Ethers D. Esters
Chemistry
2 answers:
stellarik [79]3 years ago
8 0
The answer is D.esters...only esters has a smell
rusak2 [61]3 years ago
6 0
Both carboxylic acids and esters are organic compounds with C=O bonds, however carboxylic acids contain very polar O-H groups which can hydrogen bond while esters do not. Therefore carboxylic acids have generally relatively high boiling points and are therefore not very volatile, while esters are. Additionally, esters tend to have strong aromas, and are used in many flavoured and scented products, while carboxylic acids are not. So the answer is D, esters.
Hope this helps!
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Compared to a 0.1 M aqueous solution of NaCl, a 0.8 M aqueous solution of NaCl has a
Fudgin [204]
The correct answer is option 2. A 0.8 M aqueous solution of NaCl has a higher boiling point and a lower freezing point than a 0.1 M aqueous solution of NaCl. This is explained by the colligative properties of solutions. For the two properties mentioned, the equation for the calculation of the depression and the elevation is expressed as: ΔT = -Km and <span>ΔT = Km, respectively. As we can see, concentration and the change in the property has a direct relationship.</span>
3 0
3 years ago
I performed an experiment and mixed copper nitrate and potassium iodide. When they reacted, they formed a precipitate, even thou
Alexus [3.1K]

Answer:

2Cu2^+ + 2I^- ----> 2Cu^+ + I2

Explanation:

The reaction performed in the experiment is;

2 Cu(NO3)2 + 4 KI → 2 CuI (s) + 4 KNO3 + I2

The iodide ions reduces Cu^2+ to Cu^+ which is insoluble in water hence the precipitate. This is so because iodine is a good oxidizing agent seeing that it requires one electron to fill its outermost shell. Potassium on the other hand is a good reducing agent since it easily looses its one electron.

The oxidation - reduction equation is as follows;

2Cu2^+ + 2e ----> 2Cu^+ reduction half equation

2I^- ----> I2 + 2e. Oxidation half equation

Balanced redox reaction equation;

2Cu2^+ + 2I^- ----> 2Cu^+ + I2

3 0
3 years ago
2) Nitrogen gas will react with hydrogen gas to produce ammonia, NH3, How many
Delicious77 [7]

Answer:

12 grams of hydrogen gas

and 56 grams of nitrogen gas

The molar mass of ammonia is 17 g/mol.

68 grams of ammonia corresponds to  

17g/mol

68g

​

=4moles

4 moles of ammonia will be obtained from  

2

4×1

​

=2  moles of nitrogen and  

2

4×3

​

=6  moles of hydrogen.

The molar masses of nitrogen and hydrogen are 28 g/mol and 2 g/mol respectively.

2 moles of nitrogen corresponds to 2×28=56  grams.

6 moles of hydrogen corresponds to 6×2=12  grams.

5 0
2 years ago
Which of the following is the best evidence for a chemical reaction?
alisha [4.7K]
C. Formation of a new substance
5 0
3 years ago
A sample of gas occurs 9.0mL at a pressure of 500mmHg. A new volume of the same sample is at 750mmHg. Use two significant figure
Anit [1.1K]

Answer:

V₂ = 6.0 mL

Explanation:

Given data:

Initial volume = 9.0 mL

Initial pressure = 500 mmHg

Final volume = ?

Final pressure = 750 mmHg

Solution:

According to Boyle's Law

P₁V₁ = P₂V₂

V₂ = P₁V₁ / P₂

V₂ = 500 mmHg × 9.0 mL / 750 mmHg

V₂ = 4500 mmHg .mL / 750 mmHg

V₂ = 6.0 mL

5 0
3 years ago
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