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abruzzese [7]
3 years ago
10

_______ are organic compounds containing a C=O bond, having strong aromas, and known for being volatile. A. Carboxylic acids B.

Amines C. Ethers D. Esters
Chemistry
2 answers:
stellarik [79]3 years ago
8 0
The answer is D.esters...only esters has a smell
rusak2 [61]3 years ago
6 0
Both carboxylic acids and esters are organic compounds with C=O bonds, however carboxylic acids contain very polar O-H groups which can hydrogen bond while esters do not. Therefore carboxylic acids have generally relatively high boiling points and are therefore not very volatile, while esters are. Additionally, esters tend to have strong aromas, and are used in many flavoured and scented products, while carboxylic acids are not. So the answer is D, esters.
Hope this helps!
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Lithium diisopropylamide (LDA) is used as a strong base in organic synthesis. LDA is itself prepared by an acid-base reaction be
kakasveta [241]

Explanation:

Lithium diisopropylamide (LDA) is used in many organic synthesis and is a strong base. It is prepared by the acid base reaction of N,N-diisopropylamine ( [(CH₃)₂CH]₂NH ) and butyllithium ( Li⁺⁻CH₂CH₂CH₂CH₃ ).

The equation is show below as:

[(CH₃)₂CH]₂NH + Li⁺⁻CH₂CH₂CH₂CH₃  ⇒  [(CH₃)₂CH]₂N⁻Li⁺  + CH₃CH₂CH₂CH₃

N,N-diisopropylamine ( [(CH₃)₂CH]₂NH ) is a weaker acid and hence,  LDA ( [(CH₃)₂CH]₂N⁻Li⁺ ) is stronger base. (Weaker acid has stronger conjugate base)

Butyllithium ( Li⁺⁻CH₂CH₂CH₂CH₃ ) is a very strong base and hence, butane ( CH₃CH₂CH₂CH₃ ) is a very weak acid. (Strong base has weaker conjugate acid)

5 0
3 years ago
How many grams Kl are needed to prepare 100.mL of 0.55M solution?​
Makovka662 [10]

Answer:

Explanation:

100mL = 0.1L

0.55 M = mol/0.1 L

mol = 0.055 mol

molar mass of KI = 165.998 g

0.055 * 165.998 = 9.13 g of KI

7 0
2 years ago
Select the letter of a category on which you should focus when proofreading.
oee [108]
B. Who, what, when, where, why, and how. Those are the most important and key componants in a story.
8 0
3 years ago
What is Industrial chemistry?​
mel-nik [20]

Answer:

study of chemical used in industries

6 0
3 years ago
Vinegar contains carbon, hydrogen, and oxygen with percent masses of 40.01% C, 6.70% H, and 53.29% O, respectively. Determine th
kobusy [5.1K]

The empirical formula is = C2H4O2

Molecular formula=C2H4O2

<h3>Calculation of Molecular formula and empirical formula:-</h3>

Vinegar has three elements:

oxygen = 53.29%,

hydrogen = 6.70%,

and carbon = 40.01%.

We can create an equation for the total mass of vinegar with 'a' carbon atom,' b' hydrogen atom, and 'c' oxygen atoms using the molar masses of C, H, and O.

12*a + 1*b + 16*c = 60

We also know that C makes up 24 g/mol, or 40.01 percent, of the overall mass of 60 g/mol.

The formula contains two C atoms because each C atom has a molecular mass of 12 g/mol. You may determine that the formula contains 4 H and 2 O atoms by using the same reasoning for H and O.

The empirical formula is = C2H4O2

Molecular formula= (C2H4O2)n

(4 x 12 + 1 x 4 + 16 x 2)n = 60

(84)n = 60

n=60/84

n=0.71=1

Molecular formula=C2H4O2

Learn more about Molecular and empirical formulas here:-

brainly.com/question/9207476

#SPJ4

3 0
2 years ago
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