Question

A solution contains 0.140 mol KCl in 2.100 L water. What is the concentration of KCl in g/L?

Answer 1

Answer;

≈ 4.95 g/L

Explanation;

The molar mass of KCl = 74.5 g/mole

Therefore; 0.140 moles will be equivalent to ;

 = 0.140 moles × 74.5 g/mole

 = 10.43 g

Concentration in g/L

   = mass in g/volume in L

   = 10.43/2.1

   =  4.9667

  ≈ 4.95 g/L