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Mnenie [13.5K]
3 years ago
13

An incident ray through the focal point of a spherical mirror will:

Physics
2 answers:
Strike441 [17]3 years ago
6 0

Answer:

option (c)

Explanation:

There are the rules to draw the ray diagrams for a mirror.

1. If a ray is incident on a spherical mirror parallel to the principal axis, then after reflection it passes through the focus of the mirror.

2. If a ray is incident on the spherical mirror passing through the focus, then after reflection it becomes parallel to the principal axis.

3. If a ray is incident on the spherical mirror passes through the centre of curvature then after reflection is retraces its path.

So, is an incident ray passes through the focal point of the spherical mirror, then it reflect parallel to the principal axis.

Delvig [45]3 years ago
3 0
Reflect parallel of the principal axis
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The sound intensity at a distance 2.00 m from a sound source is 5.00 Find the total sound energy emitted by the source in each s
notka56 [123]

Answer:

     P = 251, 3 W

Explanation:

The intensity is defined as the power emitted per unit area

           I = P / A

Since sound is distributed in all directions spherical shape, the area of ​​a sphere is

           A = 4π r²

let's clear the power and replace

         P = I A

         P = I (4π r²)

let's calculate

         P = 5.00 (4π 2²)

         P = 251, 3 W

6 0
3 years ago
A 5kg ball is on top of the school building at a height of 40m above the ground.
mojhsa [17]

Answer:

A-Caclcuate the potential energy of the ball at that height

Explanation:

(a). Mass of the Body = 10 kg.

Height = 10 m.

Acceleration due to gravity = 9.8 m/s².

Using the Formula,Potential Energy = mgh

= 10 × 9.8 × 10 = 980 J.

(b). Now, By the law of the conservation of the Energy, Total amount of the energy of the system remains constant.

∴ Kinetic Energy before the body reaches the ground is equal to the Potential Energy at the height of 10 m.

∴ Kinetic Energy = 980 J.

(c). Kinetic Energy = 980 J.

Mass of the ball = 10 kg.

∵ K.E. = 1/2 × mv²

∴ 980 = 1/2 × 10 × v²

∴ v² = 980/5

⇒ v² = 196

∴ v = 14 m/s.

3 0
2 years ago
Reflection of the images example
NISA [10]

Answer:

reflection of water ,sound and water waves etc

8 0
3 years ago
) A 1000 kg car travelling at 50 m/s slams into a 1500 kg parked truck in an inelastic manner as
solmaris [256]

(a)

KE = m v^2 / 2 = (1200 kg)(20 m/s)^2 / 2 = 240,000 J


(b)

The energy is entirely dissipated by the force of friction in the brake system.


(c)

W = delta KE = KEf - KEi = (0 - 240,000) J = -240,000 J



(d)

Fd = delta KE

F = (delta KE) / d = (-240,000 J) / (50 m) = -4800 N

The magnitude of the friction force is 4800 N.
8 0
3 years ago
Which of the following is not a component of fitness? A. Cardiovascular fitness B. Muscular endurance C. Pulmonary endurance D.
Ne4ueva [31]

Answer:

C. Pulmonary endurance

Explanation:

I'm pretty sure it's "C" because cardiovascular and pulmonary endurance are the same thing and usually you'd hear cardiovascular more than pulmonary.

Sorry if I'm wrong!

7 0
3 years ago
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