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2 years ago

An incident ray through the focal point of a spherical mirror will:

Physics

2 answers:

Strike441 [17]2 years ago

6 0

Answer:

option (c)

Explanation:

There are the rules to draw the ray diagrams for a mirror.

1. If a ray is incident on a spherical mirror parallel to the principal axis, then after reflection it passes through the focus of the mirror.

2. If a ray is incident on the spherical mirror passing through the focus, then after reflection it becomes parallel to the principal axis.

3. If a ray is incident on the spherical mirror passes through the centre of curvature then after reflection is retraces its path.

So, is an incident ray passes through the focal point of the spherical mirror, then it reflect parallel to the principal axis.

Delvig [45]2 years ago

3 0

Reflect parallel of the principal axis

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I think every 6 hours would be correct

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2 years ago

Erik Erikson’s theory of psychosocial development emphasizes that development occurs by overcoming an emotional crisis in each o

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1 year ago

A security guard walks at a steady pace traveling 170 m in one trip around the perimeter of a building.

WARRIOR [948]

Speed= distance/time
Speed= 170/230
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3 years ago

A plane flies from base camp to lake a, 200 km away in the direction 20.0° north of east. after dropping off supplies it flies t

Liono4ka [1.6K]

Distance of lake a is 200 km at 20 degree north of east

distance between lake a and b is 230 km at 30 degree west of north

now the distance between base and lake b is given as

$d = d_1 + d_2$

given that

$d_1 = 200 cos20 i + 200 sin20 j$

$d_1 = 187.94 i + 68.4 j$

$d_2 = -230 sin30 i + 230 cos30 j$

$d_2 = -115 i + 199.2 j$

now the total distance is

$d = (187.94 - 115)i + (199.2 + 68.4)j$

$d = 72.94 i + 267.6 j$

now the magnitude of the distance is given as

$d = \sqrt{72.94^2 + 267.6^2}$

$d = 277.4$

also the direction is given as

$\theta = tan^{-1}\frac{267.6}{72.94}$

$\theta = 74.7 degree$

<em>so it is 277.4 km at 74.7 degree North of East</em>

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2 years ago

A meteoroid is traveling east through the atmosphere at 18. 3 km/s while descending at a rate of 11.5 km/s. What is its speed, i

Annette [7]

Answer:

The speed of meteoroid is 21.61 km/s in south-east.

Explanation:

Given that,

A meteoroid is traveling through the atmosphere at 18.3 km/s. while descending at a rate of 11.5 km/s it means 11.5 km/s in south.

We need to draw a diagram

Using Pythagorean theorem

$AC^2=AB^2+BC^2$

$AC^2=(18.3)^3+(11.5)^2$

$AC=\sqrt{(18.3)^2+(11.5)^2}$

$AC=21.61\ km/s$

Hence, The speed of meteoroid is 21.61 km/s in south-east.

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2 years ago