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Aleks04 [339]
3 years ago
13

a 95.00 kg man on ice skates catches a moving ball at 18 m/s. the man is initially at rest. the man and ball move together after

the collision. the ball's mass is 0.14 kg. what is the final velocity?
Physics
1 answer:
nekit [7.7K]3 years ago
4 0
We can use conservation of momentum of the ball-man system.

mv + mv = mv

the total momentum of the two objects before the collision is the same as the total momentum of the two objects after the collision

(95)(0) + (0.14)(18) = (95 + 0.14)Vfinal

0 + 2.52 = 95.14Vf

divide by 95.14 on both sides

Final velocity = 0.0265m/s in the direction the ball was initially travelling
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A jet transport has a weight of 2.25 x 106 N and is at rest on the runway. The two rear wheels are 16.0 m behind the front wheel
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Answer:

Explanation:

Given that,

Weight of jet

W = 2.25 × 10^6 N

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Two rear wheels are 16m behind the front wheel

Center of gravity of plane 10.6m behind the front wheel

A. Normal force entered on the ground by front wheel.

Taking moment about the the about the real wheel.

Check attachment for better understanding

So,

Clock wise moment = anti-clockwise moment

W × 5.4 = N × 16

2.25 × 10^6 × 5.4 = 16•N

N = 2.25 × 10^6 × 5.4 / 16

N = 7.594 × 10^5 N

B. Normal force on each of the rear two wheels.

Using the second principle of equilibrium body.

Let the rear wheel normal be Nr and note, the are two real wheels, then, there will be two normal forces

ΣFy = 0

Nr + Nr + N — W = 0

2•Nr = W—N

2•Nr = 2.25 × 10^6 — 7.594 × 10^5

2•Nr = 1.491 × 10^6

Nr = 1.491 × 10^6 / 2

Nr = 7.453 × 10^5 N

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You have a 16-kg suitcase. what work did you do when you have slowly lifted it 0.80 m upward?
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