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stellarik [79]
3 years ago
13

40ml of Liquid A are poured into a beaker, and 40.0ml of Liquid B are poured into an identical beaker. Stirrers in each beaker a

re connected to motors, and the forces FA and FB needed to stir each liquid at a constant rate are measured.
a. FA will be greater than F B
b. FA will be less than FB
c. FA will be equal to FB
d. It's impossible to predict whether FA or FB will be greater without more information.
Physics
1 answer:
lakkis [162]3 years ago
7 0

Answer:

d

Explanation:

there is not enough information about the liquid to know the force required for each. ie. stirring a cup of water is different than stirring a cup of pudding.

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Paha777 [63]

Answer:

=140 cm²

Explanation:

1

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___ x base × height

is the formula have a gr8 day :)

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5 0
3 years ago
According to Coulomb's law, if the separation between two particles of the same charge increases four times, the potential energ
Lera25 [3.4K]

Answer:

c.   V = k Q1 * Q2 / R1      potential energy of Q1 and Q2 separated by R

V2 / V1 = (R1 / R2) = 1/4

V2 = V1 / 4

8 0
3 years ago
An Apple falls from a tree and one-half second later hits the ground
docker41 [41]
There isnt enough information to answer the question, the missing variable is "distance from said falling spot and ground"
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3 years ago
When approaching an intersection, bridge, or railroad crossing, you should never drive (pass on the left half of the roadway whe
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8 0
3 years ago
Car A has a mass of 1,200 kg and is traveling at a rate of 22 km/hr. It collides with car B. Car B has a mass of 1,900 kg and is
anastassius [24]

The car A has a mass of 1200 kg.

The car B has the mass of 1900 kg.

It is given that velocity of car  A is given as 22 Km/hr

The car B has the velocity of 25 Km/hr.

Let the mass of two bodies are denoted as  m_{1} \ and\ m_{2}

Let the velocity of cars A and B are denoted as v_{1} \ and\ v_{2}

The momentum before collision is-

                                                  p_{i} =m_{1} v_{1} +m_{2} v_{2}

[Here p stand for momentum.]

We are asked to calculate the final momentum of the system after collision.

The answer of the question is based law of conservation of  linear momentum.

As per law of conservation of linear momentum the sum total linear momentum for an isolated system is always constant.Hence irrespective of the type of collision[elastic and inelastic],the momentum of the system is always constant which is a universal truth.

Let after the collision the velocity of A and B are v'_{1} \ and\ v'_{2}

Hence the final momentum of the system is-

                                                        p_{f} = m_{1} v'_{1} +m_{2} v'_{2}

As per the law of conservation of linear momentum, the initial and final momentum must be equal i.e      

                              p_{i} =p_{f}

                               m_{1} v_{1} +m_{2}v_{2} =m_{1} v'_{1} +m_{2} v'_{2}

Hence the option A  is right.

7 0
3 years ago
Read 2 more answers
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