An airplane flying at 116 m/s. E, is accelerated uniformly at the rate of 9.2 m/s2, E, for 13 s. What is its final velocity in m
1 answer:
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Answer:
1946 ft
Explanation:
The distance is the addition of the distance gotten from both triangles.
d = x + y
d = 1178 ft + 768 ft
d = 1946 ft
Attached is a picture showing how I arrived at the answer
Answer:
Time = t = 6.62 s
Explanation:
Given data:
Height = h = 215 m
Initial velocity = = 0 m/s
gravitational acceleration = g = 9.8 m/s²
Time = t = ?
According to second equation of motion
As initial velocity is zero, So the first term of right hand side of above equation equal to zero.
t² =
t =
t =
t = 6.62 s
Answer:
h = 0.362 m
Explanation:
The pressure equation with depth is
P₂ = +ρ g h
The gauge pressure is
P2 - = ρ g h
This is the pressure that muscles can create
P₂ - = 3740 Pa
But still the person needs a small pressure for the transfer of gases, so
P₂ - = 3740 - 188 = 3552 Pa
This is the maximum pressure difference, where the person can still breathe,
Let's clear the height
h = 3552 / ρ g
h = 3552 / (1000 9.8)
h = 0.362 m
This is the maximum depth where the person can still breathe normally.