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aliya0001 [1]
3 years ago
7

In photograph a, a coil of zinc metal is in a solution of sulfuric acid. In photograph b, a yellow solution of sodium chromate i

s being added to a colorless solution of silver nitrate. What clues in the photographs indicate that a chemical change is probably occurring?
Chemistry
1 answer:
steposvetlana [31]3 years ago
7 0

In photograph a, a coil of zinc metal is in a solution of sulfuric acid. In photograph b, a yellow solution of sodium chromate is being added to a colorless solution of silver nitrate. What clues in the photographs indicate that a chemical change is probably occurring.

In photograph a, chemical change is occuring as when a coil of zinc metal is in a solution of sulfuric acid, then the solution starts bubbling, that indicates a chemical change.

In photograph b, a yellow solution of sodium chromate is being added to a colorless solution of silver nitrate, that changes the color of the solution to red , that indicates a chemical change.

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Polyester is a synthetic material used for many different purposes. It is produced from petroleum and natural gas. Producing pol
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When 1.0g of diethyl ether is converted to vapor at its boiling point, about how much heat is absorbed? (C4H10O, Hvap= 15.7kj/mo
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Answer:

Option D = 0.2 Kj

Explanation:

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Mass of diethyl ether = 1.0 g

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8 0
3 years ago
The half life of 226/88 Ra is 1620 years. How much of a 12 g sample of 226/88 Ra will be left after 8 half lives?
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Answer:

0.0468 g.

Explanation:

  • The decay of radioactive elements obeys first-order kinetics.
  • For a first-order reaction: k = ln2/(t1/2) = 0.693/(t1/2).

Where, k is the rate constant of the reaction.

t1/2 is the half-life time of the reaction (t1/2 = 1620 years).

∴ k = ln2/(t1/2) = 0.693/(1620 years) = 4.28 x 10⁻⁴ year⁻¹.

  • For first-order reaction: <em>kt = lna/(a-x).</em>

where, k is the rate constant of the reaction (k = 4.28 x 10⁻⁴ year⁻¹).

t is the time of the reaction (t = t1/2 x 8 = 1620 years x 8 = 12960 year).

a is the initial concentration (a = 12.0 g).

(a-x) is the remaining concentration.

∴ kt = lna/(a-x)

(4.28 x 10⁻⁴ year⁻¹)(12960 year) = ln(12)/(a-x).

5.54688 = ln(12)/(a-x).

Taking e for the both sides:

256.34 = (12)/(a-x).

<em>∴ (a-x) = 12/256.34 = 0.0468 g.</em>

8 0
3 years ago
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