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3 years ago

Why might a major volcanic eruption lead to cooler temperatures of Earth's surface?

1 answer:

6 0

When a volcano erupts it releases a large amount of dust, smog, rock, and other materials. Basically, these bits and pieces float to form a metaphorical dust cloud. These clouds can often block out the sun like an ordinary cloud; however, because the cloud is dark, even less sun will be able to get through. So because the sun can't reach the ground, the temperature might decrease.

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The water for the pan is not saturated with co2. will the reported percent caco3 in the original sample be too high, too low, or

enot [183]

Co2 will dissolve in water if water is saturated with Co2 first then it will absorb some of CO2 it appear as less is absorb that was actually the case . this would make it appear as present of CACO3 is in original sample is lower than it will be too low

8 0

3 years ago

How TO DO THIS QUESTION PLEASE PLEASEEEEEEEEEeeeeeeeeeeeeeeeeeeee

krok68 [10]

O2 is the limited reactant

3 0

2 years ago

Aluminum has a density of 2.70 g/mL. A sample of aluminum weighs 67.5 g. If this sample is put into a graduated cylinder that ha

romanna [79]

Answer:

60 ml

Explanation:

Now, we know that density = mass/volume

Mass of aluminium = 67.5 g

volume of aluminium =?

density of aluminium = 2.70 g/mL

volume of aluminium = mass/density = 67.5/2.70 = 25 ml

Since volume of water in the cylinder = 35 ml

The water rises to ; 35 ml + 25 ml = 60 ml

4 0

2 years ago

The period of daylight experienced each day on every part of Earth would be shorter if which one of the following changes occurr

lilavasa [31]

Answer:

Explanation:

5 0

2 years ago

Problem PageQuestion Aqueous sulfuric acid will react with solid sodium hydroxide to produce aqueous sodium sulfate and liquid w

quester [9]

Answer:

0.72g

Explanation:

Step 1:

We'll begin by writing a balanced equation for the reaction. This is illustrated below:

H2SO4 + 2NaOH —> Na2SO4 + 2H2O

Step 2:

Determination of the mass of sulphuric acid (H2SO4) and the mass of sodium hydroxide (NaOH) that reacted from the balanced equation. This is illustrated below:

Molar Mass of H2SO4 = (2x1) + 32 +(16x4) = 2 + 32 + 64 = 98g/mol

Molar Mass of NaOH = 23 + 16 + 1 = 40g/mol

Mass of NaOH from the balanced equation = 2 x 40 = 80g

Step 3

Determination of the limiting reactant. To do this, we need to know which of the reactant is excess.

Now let us consider using all of the mass of NaOH given to see if there will be left over for H2SO4. This is illustrated below:

From the balanced equation above,

98g of H2SO4 required 80g of NaOH.

Therefore, Xg of H2SO4 will require 1.6g of NaOH i.e

Xg of H2SO4 = (98x1.6)/80

Xg of H2SO4 = 1.96g

Now comparing the mass of H2SO4 that reacted ( i.e 1.96g) and the mass of H2SO4 given ( i.e 2.94g), we can see clearly that there are left over ( i.e 2.94 - 1.96 = 0.98g) of H2SO4. Therefore, H2SO4 is the excess reactant and NaOH is the limiting reactant.

Step 4:

Determination of the mass of water produced from the reaction. This is illustrated below:

The balanced equation for the reaction is given below:

H2SO4 + 2NaOH —> Na2SO4 + 2H2O

Molar Mass of H2O = (2x1) + 16 = 2 + 16 = 18g/mol

Mass of H2O from the balanced equation = 2 x 18 = 36g

From the balanced equation above,

80g of NaOH reacted to produced 36g of H2O.

Therefore, 1.6g of NaOH will react to produce = (1.6 x 36)/80 = 0.72g of H2O.

Therefore, the maximum mass of water (H2O) produced by the chemical reaction of aqueous sulfuric acid with solid sodium hydroxide is 0.72g

4 0

2 years ago