Proton
charge +
electron
charge -
neutron
charge neutral
Answer: 4.9 x 10^6 joules
Explanation:
Given that:
mass of boulder (m) = 2,500 kg
Height of ledge above canyon floor (h) = 200 m
Gravita-tional potential energy of the boulder (GPE) = ?
Since potential energy is the energy possessed by a body at rest, and it depends on the mass of the object (m), gravitational acceleration (g), and height (h).
GPE = mgh
GPE = 2500kg x 9.8m/s2 x 200m
GPE = 4900000J
Place result in standard form
GPE = 4.9 x 10^6J
Thus, the gravita-tional potential energy of the boulder-Earth system relative to the canyon floor is 4.9 x 10^6 joules
Answer:
I = (1.80 × 10⁻¹⁰) A
Explanation:
From Biot Savart's law, the magnetic field formula is given as
B = (μ₀I)/(2πr)
B = magnetic field = (1.0 × 10⁻¹⁵) T
μ₀ = magnetic constant = (4π × 10⁻⁷) H/m
r = 3.6 cm = 0.036 m
(1.0 × 10⁻¹⁵) = (4π × 10⁻⁷ × I)/(2π × 0.036)
4π × 10⁻⁷ × I = 1.0 × 10⁻¹⁵ × 2π × 0.036
I = (1.80 × 10⁻¹⁰) A
Hope this Helps!!!
Answer:
Approximate escape speed = 45.3 km/s
Explanation:
Escape speed

Here we have
Gravitational constant = G = 6.67 × 10⁻¹¹ m³ kg⁻¹ s⁻²
R = 1 AU = 1.496 × 10¹¹ m
M = 2.3 × 10³⁰ kg
Substituting

Approximate escape speed = 45.3 km/s
Friction
Friction also affects the movement of an object on a slope. Friction is a force that offers resistance to movement when one object is in contact with another. Imagine now that you were on the downside of the object and applying force to keep the object in the same place (not moving)