Answer:
7.78x10^-8T
Explanation:
The Pointing Vector S is
S = (1/μ0) E × B
at any instant, where S, E, and B are vectors. Since E and B are always perpendicular in an EM wave,
S = (1/μ0) E B
where S, E and B are magnitudes. The average value of the Pointing Vector is
<S> = [1/(2 μ0)] E0 B0
where E0 and B0 are amplitudes. (This can be derived by finding the rms value of a sinusoidal wave over an integer number of wavelengths.)
Also at any instant,
E = c B
where E and B are magnitudes, so it must also be true at the instant of peak values
E0 = c B0
Substituting for E0,
<S> = [1/(2 μ0)] (c B0) B0 = [c/(2 μ0)] (B0)²
Solve for B0.
Bo = √ (0.724x2x4πx10^-7/ 3 x10^8)
= 7.79 x10 ^-8 T
Answer:
D) -Q
Explanation:
The charge inserted will induce -Q charge on the inner surface and + Q on the outer surface of the shell . This charge is called bound charge because it remained attached with opposite charge inserted inside.
Answer:toward the ceiling
Explanation:
if you use the right hand rule it will point to the ceiling
Answer: 9/4n
Explanation:
Let's take T to represent tank
When n litres of fuel was added to tank that was 1/3 full = n + 1/3T
The tank was 7/9T
n+1/3T = 7/9T
n =7/9T - 1/3T
n = 4/9
If a full tank is taken to be 1 = 9/9
Hence, we will have 1 = x × n
1 = x × 4/9
x = 9/4
Hence 9/4 of n = 9/4n
