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WINSTONCH [101]
3 years ago
13

Determine qual é a carga elétrica de um corpo que possui 1 milhão de partículas?

Physics
1 answer:
MaRussiya [10]3 years ago
7 0

Answer:

This can be translated to:

"find the electrical charge of a body that has 1 million of particles".

First, it will depend on the charge of the particles.

If all the particles have 1 electron more than protons, we will have that the charge of each particle is q = -e = -1.6*10^-19 C

Then the total charge of the body will be:

Q = 1,000,000*-1.6*10^-19 C = -1.6*10^-13 C

If we have the inverse case, where we in each particle we have one more proton than the number of electrons, the total charge will be the opposite of the one of before (because the charge of a proton is equal in magnitude but different in sign than the charge of an electron)

Q = 1.6*10^-13 C

But commonly, we will have a spectrum with the particles, where some of them have a positive charge and some of them will have a negative charge, so we will have a probability of charge that is peaked at Q = 0, this means that, in average, the charge of the particles is canceled by the interaction between them.

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Answer:

50\; \rm kg.

Explanation:

By Newton's Second Law, the acceleration a of an object is proportional to the net force \sum F on it. In particular, if the mass of the object is m, then

\sum F = m \cdot a.

Rewrite this equation to obtain:

\displaystyle m = \frac{\sum F}{a}.

In this case, the assumption is that the 100\; \rm N force is the only force that is acting on the object. Hence, the net force \sum F on the object would also be

Make sure that all values are in their standard units. Forces should be in Newtons (same as \rm kg \cdot m \cdot s^{-2}, and the acceleration of the object should be in meters-per-second-squared (\rm m \cdot s^{-2}). Apply the equation \displaystyle m = \frac{\sum F}{a} to find the mass of the object.

\displaystyle m = \frac{100\; \rm N}{2\; \rm m \cdot s^{-2}} = 50\; \rm kg.

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A listener increases his distance from a sound source by a factor of 4.49.
noname [10]

Answer: Δβ (dB) = -13.1dB

Explanation:

The intensity of sound is inversely proportional to the square of the distance between them.

I ∝ 1/r²

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When the listener increases his distance from the source by a factor of 4.49.

Then,

r₂/r₁= 4.49

From equation 1

I₁/I₂ = (4.49)²

I₁/I₂ = 20.16

I₂/I₁ = 1/20.16

The change in sound intensity in dB can be given as

Δβ (dB) = 10 log(I₂/l₁) = 10log(1/20.6) = -13.1dB

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A capacitor is charges with 9.6 nC and has a 120 V potential difference between its terminals. Compute
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Explanation:

Q = CV

where C = capacitance

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= 1.15 microFarads

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