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WINSTONCH [101]
3 years ago
13

Determine qual é a carga elétrica de um corpo que possui 1 milhão de partículas?

Physics
1 answer:
MaRussiya [10]3 years ago
7 0

Answer:

This can be translated to:

"find the electrical charge of a body that has 1 million of particles".

First, it will depend on the charge of the particles.

If all the particles have 1 electron more than protons, we will have that the charge of each particle is q = -e = -1.6*10^-19 C

Then the total charge of the body will be:

Q = 1,000,000*-1.6*10^-19 C = -1.6*10^-13 C

If we have the inverse case, where we in each particle we have one more proton than the number of electrons, the total charge will be the opposite of the one of before (because the charge of a proton is equal in magnitude but different in sign than the charge of an electron)

Q = 1.6*10^-13 C

But commonly, we will have a spectrum with the particles, where some of them have a positive charge and some of them will have a negative charge, so we will have a probability of charge that is peaked at Q = 0, this means that, in average, the charge of the particles is canceled by the interaction between them.

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Answer:

2nd bscause there is a reaction

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An object is moring in a negative direction with a negative acceleration, for example an object dropped out a vindow. What does
Lina20 [59]

Answer:

Its slowing down

Explanation:

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5 0
2 years ago
A hockey puck slides off the edge of a platform with an initial velocity of 20 m/s horizontally. The height of the platform abov
Rina8888 [55]

Answer:

20.96 m/s

Explanation:

Using the equations of motion

y = uᵧt + gt²/2

Since the puck slides off horizontally,

uᵧ = vertical component of the initial velocity of the puck = 0 m/s

y = vertical height of the platform = 2 m

g = 9.8 m/s²

t = time of flight of the puck = ?

2 = (0)(t) + 9.8 t²/2

4.9t² = 2

t = 0.639 s

For the horizontal component of the motion

x = uₓt + gt²/2

x = horizontal distance covered by the puck

uₓ = horizontal component of the initial velocity = 20 m/s

g = 0 m/s² as there's no acceleration component in the x-direction

t = 0.639 s

x = (20 × 0.639) + (0 × 0.639²/2) = 12.78 m

For the final velocity, we'll calculate the horizontal and vertical components

vₓ² = uₓ² + 2gx

g = 0 m/s²

vₓ = uₓ = 20 m/s

Vertical component

vᵧ² = uᵧ² + 2gy

vᵧ² = 0 + 2×9.8×2

vᵧ = 6.26 m/s

vₓ = 20 m/s, vᵧ = 6.26 m/s

Magnitude of the velocity = √(20² + 6.26²) = 20.96 m/s

4 0
3 years ago
Read 2 more answers
a battery is connected to a resistor. as charge flows, the chemical energy of the battery is dissipated as _________.
balandron [24]

As charge flows, the chemical energy of the battery is dissipated as the time of charge flow increases.

Electric power is defined as the rate at which electric energy is dissipated.

The power of the current flowing through the circuit is calculated as follows;

P = IV

P = I x IR

P = I²R

where;

  • <em>P is the power dissipated</em>
  • <em>I is the current flowing in the circuit</em>
  • <em>R is the resistance of the circuit</em>

The electric energy is given as;

E = Pt

E = I²Rt

Thus, we can conclude that as charge flows, the chemical energy of the battery is dissipated as the time of charge flow increases.

Learn more here:brainly.com/question/21392880

5 0
2 years ago
a 0.60 kg ball is moving horizontally with a speed of 5.7 m/s when it strikes a vertical wall. the ball rebounds with a speed of
elixir [45]

We can use the following equation to solve this problem:

<h3>Δp=m∣Vi−Vf∣</h3>

(Where p is the momentum change, m is mass, Vi is initial velocity, and

Vf is final velocity)

Substitute the values given to us in the question:

Δp=(0.6)∣(5.7−(−2.7)∣

Δp=4.9 kg.m/s

Final answer: 4.9kg.m/s.

The change in momentum (Δp) is defined as the change in the mass times the velocity of an object. A force is required to change the momentum of an object. This applied force can increase or decrease momentum, or even change the orientation of an object.

Learn more about momentum:

https://brainly.in/question/1535814

#SPJ4

5 0
9 months ago
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