Given:
The frequency of the pendulum ( f) = 0.25 Hz.
Total time (t) = 10 s
Concept: Frequency means, the number of oscillation in one second.
Time period is the required time by pendulum to complete one oscillation.
∵ In 1.0 second, number of oscillations = 0.25
∴ In 10.0 second, number of oscillations = (0.25 ×10.0) / 1.0 = 2.5
Hence, the required number of oscillation = 2.5
Although the video is not found here, the sentence makes reference to the transmission spectrum of colored filters.
<h3>What is the transmission spectrum?</h3>
The transmission spectrum indicates the light portion having a given wavelength that can be passed through a filter.
This spectrum (transmission spectrum) depends on the physical separation of the particles that form the filter.
In conclusion, although the video is not found here, the sentence makes reference to the transmission spectrum of colored filters.
Learn more about the transmission spectrum here:
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Answer:
<em> -11,813.87N </em>
Explanation:
According to coulombs law, the Force between the two charges is expressed as;
F = kq1q2/d²
k is the coulombs constant = 9*10⁹kg⋅m³⋅s⁻²⋅C⁻².
q1 = -0.00067 C
q2 = 0.00096 C
d = 0.7m
Substitute into the formula:
F = 9*10^9 * -0.00067 * 0.00096/0.7²
F = 9*10⁹*-6.7*10⁻⁴*9.6*10⁻⁴/0.49
F = -578.88*10⁹⁻⁸/0.49
F = -578.88*10/0.49
F = -5788.8/0.49
F = -11,813.87N
<em>Hence the force between the two charges is -11,813.87N </em>
a. The speed of the tsunami at ocean depth of 8000 m is 1,019.66 km/h.
b. The speed of the tsunami at ocean depth of 3500 m is 660.75 km/h.
c. The speed of the tsunami at ocean depth of 70 m is 89.66 km/h.
d. The speed of the tsunami at ocean depth of 5 m is 30.625 km/h.
<h3>
Speed of the tsunami at the given depths</h3>
The speed of the tsunami is calculated from method of extrapolation or interpolation as shown below;
<h3>Speed at 8000 meters</h3>
8000 m -------- ?
7000 m -------- 943 km/h
4000 m -------- 713 km/h
(8000 - 7000)/(7000 - 4000) = (? - 943)/(943 - 713)
0.3333 = (? - 943)/230
230(0.3333) = ? - 943
76.66 = ? - 943
? = 1,019.66 km/h
<h3>Speed at 3500 m</h3>
4000 m ---------- 713 km/h
3500 m ---------- ?
2000 m ----------- 504 km/h
(4000 - 3500)/(4000 - 2000) = (713 - ?) / (713 - 504)
0.25 = (713 - ?) /209
0.25(209) = 713 - ?
52.25 = 713 - ?
? = 660.75 km/h
<h3>Speed at 70 m</h3>
200 m ------ 159 km/h
70 m --------- ?
50 m ------- 79 km/h
(200 - 70)/(200 - 50) = (159 - ?)/(159 - 79)
0.8667 = 159 - ? / 80
80(0.8667) = 159 - ?
69.336 = 159 - ?
? = 89.66 km/h
<h3>Speed at 5 meters</h3>
50 m ------- 79 km/h
10 m --------- 36 km/h
5 m ---------- ?
(50 - 5)/(50 - 10) = (79 - ?)/(79 - 36)
1.125 = 79 - ?/43
43(1.125) = 79 - ?
48.375 = 79 - ?
? = 30.625 km/h
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