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ozzi
3 years ago
5

How would you describe the behavior of particles in a solid?

Physics
2 answers:
Minchanka [31]3 years ago
4 0
How would you describe the behavior of particles in a solid?
vichka [17]3 years ago
4 0
You could say they are not very active but still have very little movement rather then a gas where the particles are moving fast
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A merry-go-round, with mass m and moment
andriy [413]
It goes around the x axis
4 0
4 years ago
A projectile is fired at an upward angle of 35.6° from the top of a 208-m-high cliff with a speed of 170-m/s. What will be its s
sdas [7]

Answer:

Final velocity is 181.61 m/s at angle 40.44° below horizontal.

Explanation:

Initial horizontal velocity = 170 cos 35.6 = 138.23 m/s

Final horizontal velocity = 138.23 m/s

Considering vertical motion of projectile:

Initial vertical velocity, u = 170 sin 35.6 = 98.96 m/s

Acceleration, a = -9.81 m/s²

Displacement, s = -208 m

We have v² = u² + 2as

Substituting

             v² = 98.96² + 2 x -9.81 x -208

             v = 117.79 m/s

Final velocity,

            v=\sqrt{138.23^2+117.79^2}=181.61m/s

            \theta =tan^{-1}\left ( \frac{117.79}{138.23}\right )=40.44^0

Final velocity is 181.61 m/s at angle 40.44° below horizontal.

5 0
4 years ago
What is the Kinetic Energy of a 5kg object traveling at 10 m/s?
Marat540 [252]

Answer:

KE = 250 kg/m/s

Explanation:

use the formula: KE = 1/2 m (v^2)

KE = 1/2 (5) (10^2)

KE = (2.5) (100)

KE = 250 kg/m/s

3 0
3 years ago
You short-circuit a 18 volt battery by connecting a short wire from one end of the battery to the other end. if the current in t
mina [271]
The relationship between the voltage and the current in the circuit is:
\Delta V = RI
where \Delta V is the voltage difference, R the resistance of the circuit (and therefore, the resistance of the battery) and I the current flowing in the circuit. By using I=19 A and \Delta V = 18 V, we can find the internal resistance of the battery:
R= \frac{\Delta V}{I}= \frac{18 V}{19 A}=0.95 \Omega
3 0
3 years ago
Molecular chlorine and molecular fluorine combine to form a gaseous product. Under the same conditions of temperature and pressu
kotegsom [21]
In this equation

1 Cl2 + 3 F2---> 2 ClxFy

those coefficients are in MOLE (or molecule) ratios. BUT for gases at the same temp and pressure, they are also VOLUME ratios.. why? PV = nRT, V = nRT/P. if RT/P = constant.. V1/n1 = V2/n2 --> n1/n2 = V1/V2..make sense? mole ratios
= volume ratios

so.. what are x and y?
1 Cl2 + 3 F2---> 2 ClxFy

2 Cl's on the left.. x must = 1
6 F2's on the left. y must be 3

1 Cl2 + 3 F2---> 2 ClF3 <span>
</span>
6 0
4 years ago
Read 2 more answers
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