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3 years ago

10

What do you call the point of interest on a velocity versus time graph?

1 answer:

valina [46]3 years ago

7 0

Answer:

Explanation:

The principle is that the slope of the line on a velocity-time graph reveals useful information about the acceleration of the object. If the acceleration is zero, then the slope is zero (i.e., a horizontal line). If the acceleration is positive, then the slope is positive (i.e., an upward sloping line).

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agasfer [191]

Answer:

i/f = i/o + i/i f = focal, o = object, i = image

1 / i = 1 / f - 1 / o = (o - f) / o f

i = o * f / ( o - f) image distance

i = 12.5 * 22 / (12.5 - 22) = -28.9 cm

Image is real

Image is 28.9 cm to left of lens

M = - i / o = = 28.9 / 12.5 = 2.3 magnification (convex lens)

8 0

3 years ago

Elsie is finishing second grade. If she goes to school 147 day per year and she have 10 years of school left, how many days of s

ICE Princess25 [194]

Answer:

1,323 days left

Explanation:

147 x 10 = 1,470

1470 - 147 = 1,323

Hopefully this helps you :)

pls mark brainlest ;)

6 0

3 years ago

Find the slope of the line containing the two points (1,−1) and (−5,−3). (1 point)

grandymaker [24]

Answer:

(-4,-2)

Explanation:

4 0

3 years ago

A force is always needed to slow an object down.<br><br> A True<br> B false

Fiesta28 [93]

The answer is TRUE, I'm pretty sure.

5 0

3 years ago

When a constant force acts upon an object, the acceleration of the object varies inversely with its mass 2kg. When a certain con

BARSIC [14]

Answer:

The acceleration of the second object is 4 m/s².

Explanation:

Given that,

when the a constant force acts upon an object, the acceleration varies inversely with its mass .

$mass\propto \frac{1}{acceleration}$

We can rewrite the equation as

$\frac{m_1}{m_2}=\frac{a_2}{a_1}$

When an a certain constant force acts upon an object with mass 2 kg , the acceleration of the object is 26 m/s².

Here, $m_1$ = 2 kg, $a_1$ = 26 m/s², $m_2$ = 13 kg and $a_2=?$

$\frac{m_1}{m_2}=\frac{a_2}{a_1}$

$\frac{2}{13}=\frac{a_2}{26}$

$\Rightarrow \frac{a_2}{26}= \frac{2}{13}$

$\Rightarrow {a_2}= \frac{2}{13}\times 26$

$\Rightarrow a_2=4$ m/s²

The acceleration of the second object is 4 m/s².

3 0

3 years ago