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9966 [12]
3 years ago
6

Where is the center of mass of the Earth-Moon system? The radius of the Earth is 6378 km and the radius of the Moon is 1737 km.

Select one of the answers below: Choose the correct description of the location of the center of mass of the Earth-Moon system. Choose the correct description of the location of the center of mass of the Earth-Moon system. The center of mass is exactly in the center between the Earth and the Moon. The center of mass is nearer to the Moon than the Earth, but outside the radius of the Moon. The center of mass is nearer to the Earth than the Moon, but outside the radius of the Earth.
Physics
1 answer:
lions [1.4K]3 years ago
3 0

Answer:

r_{cm} = 4.67 10⁶ m

We see that none of the answers is correct, the closest is the third, but the center of mass is within the radius of the Earth

Explanation:

The definition of the center of mass is

      r_{cm} = 1 / M ∑r_{i}  m_{i}

Where M is the total mass, r_{i} and m_{i}mi are the position and the mass gives each of the bodies

We must locate a reference system for the calculation, we will locate it with the origin in the center of the Earth, the data we have are

Mass of the Earth Me = 5.98 1024 kg

Moon mass m = 7.36 1022 kg

Earth to Moon Distance r = 3.84 108 m

Let's apply this to our case

      r_{cm} = 1 / (Me + m) (Me 0 + m R)

      r_{cm} = 1 / (598 +7.36) 10²² (0 + 7.36 10²² 3.84 10⁸)

     r_{cm} = 4.67 10⁶ m

We can see that this distance is less than the radius of the Earth

We see that none of the answers is correct, the closest is the third, but the center of mass is within the radius of the Earth

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Sally is on a canoe that comes to a stop a small distance from the dock. Since it is such a small distance, Sally decides to jum
natita [175]

Answer:

 v₂> v₃  velocity canoe is more than velocity fishing boat

Explanation:

For this exercise we must define a system consisting of the girl, Sally and the boat, in one case the canoe and in the other the fishing boat; for this system we can use moment conservation

Initial moment. Before the jump

           p₀ = (M + m₂) v

Final moment. After the jump

          p_{f} = M v₁ - m₂ v₂

Where m and v are the masses and speed of the canoe

          p₀ = p_{f}

          (M + m₂) v = M v₁ - m₂ v₂

In the case of changing the canoe for the heaviest fishing boat, the final moment is

          p_{f} = M v₁ - m₃ v₃

          p₀ = p_{f}

           (M + m₃) v = M v₁ - m₃ v₃

Since the canoe is stopped the speed v = 0, we write the speed of each boat

Canoe

          0 = M v₁ - m₂ v₂

          v₂ = M / m₂ v₁

Fishing boat

        0 = M v₁ - m₃ v₃

        v₃ = M / m₃ v₁

Since the masses of the fishing boat (m₃) is greater than the mass of the canoe (m₂) the speed of the fishing boat is less than the speed of the canoe, we can find the relationship between the two speeds

        v₂ / v₃ = m₃ / m₂

Here you can see what  v₂> v₃  velocity canoe is more than velocity fishing boat

8 0
3 years ago
Which equation describes the line containing the points (-2, 3) and (1, 2)​
snow_lady [41]

Answer:

y =  \frac{ - 1}{3}x +  \frac{7}{3}

Explanation:

\frac{y - 3}{2 - 3}  =  \frac{x + 2}{1 + 2}  \\  \ - y + 3 =  \frac{x + 2}{3}  \\  y =   \frac{ - 1}{3}x  +  \frac{7}{3}

8 0
3 years ago
a microwave uses a 14 a of electricity if 120 v is run through it what is the resistance of the microwave
Airida [17]
Resistance = voltage / current.

That's. 120v / 14A = 8.57 ohms.

By the way, voltage doesn't "run through" anything. Current does. That would be the 14 Amps.
5 0
3 years ago
Calculate the gravitational attraction between two objects which masses are: mass A: 2.5kg, mass B: 5kg. The distance between th
jonny [76]

From the calculation, the gravitational force of attraction is  1.33 * 10^-14 N.

<h3>What is the gravitational force?</h3>

The gravitational force is an attractive force that acts between any two masses.

It is given by;

F = Gm1m2/r^2

F = 6.67 * × 10−11 * 2.5 * 5/(250)^2

F  = 83.4  × 10−11 /62500

F= 1.33 * 10^-14 N

Learn more about gravitational force:brainly.com/question/12528243

#SPJ1

4 0
2 years ago
If the primary of a transformer were connected to a dc power source,
QveST [7]

Answer:

D. only briefly while being connected or disconnected.

Explanation:

As we know that transformer works on the principle of mutual inductance

here we know that as per the principle of mutual inductance when flux linked with the primary coil charges then it will induce EMF in secondary coil

So here when AC source is connected with primary coil then it will give output across secondary coil because AC source will have change in flux with time.

Now when we connect DC source across primary coil then it will not induce any EMF across secondary coil because DC source is a constant voltage source in which flux will remain constant always

So here in DC source the EMF will only induce at the time of connection or disconnection when flux will change in it while rest of the time it will give ZERO output

so correct answer will be

D. only briefly while being connected or disconnected.

8 0
3 years ago
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