Answer:
a
![\lambda = 3.68 *10^{-36} \ m](https://tex.z-dn.net/?f=%5Clambda%20%3D%203.68%20%2A10%5E%7B-36%7D%20%5C%20%20m)
b
![\lambda_p = 1.28*10^{-14} \ m](https://tex.z-dn.net/?f=%5Clambda_p%20%3D%201.28%2A10%5E%7B-14%7D%20%5C%20m)
Explanation:
From the question we are told that
The mass of the person is ![m = 180 \ kg](https://tex.z-dn.net/?f=m%20%3D%20%20180%20%5C%20%20kg)
The speed of the person is ![v = 1 \ m/s](https://tex.z-dn.net/?f=v%20%20%3D%20%201%20%5C%20%20m%2Fs)
The energy of the proton is ![E_ p = 5 MeV = 5 *10^{6} eV = 5.0 *10^6 * 1.60 *10^{-19} = 8.0 *10^{-13} \ J](https://tex.z-dn.net/?f=E_%20p%20%3D%20%205%20MeV%20%3D%205%20%2A10%5E%7B6%7D%20eV%20%20%3D%205.0%20%2A10%5E6%20%2A%201.60%20%2A10%5E%7B-19%7D%20%3D%208.0%20%2A10%5E%7B-13%7D%20%5C%20%20J)
Generally the de Broglie wavelength is mathematically represented as
![\lambda = \frac{h}{m * v }](https://tex.z-dn.net/?f=%5Clambda%20%3D%20%5Cfrac%7Bh%7D%7Bm%20%2A%20v%20%7D)
Here h is the Planck constant with the value
![h = 6.62607015 * 10^{-34} J \cdot s](https://tex.z-dn.net/?f=h%20%3D%206.62607015%20%2A%2010%5E%7B-34%7D%20J%20%5Ccdot%20s)
So
![\lambda = \frac{6.62607015 * 10^{-34}}{ 180 * 1 }](https://tex.z-dn.net/?f=%5Clambda%20%3D%20%5Cfrac%7B6.62607015%20%2A%2010%5E%7B-34%7D%7D%7B%20180%20%20%2A%201%20%20%7D)
=> ![\lambda = 3.68 *10^{-36} \ m](https://tex.z-dn.net/?f=%5Clambda%20%3D%203.68%20%2A10%5E%7B-36%7D%20%5C%20%20m)
Generally the energy of the proton is mathematically represented as
![E_p = \frac{1}{2} * m_p * v^2_p](https://tex.z-dn.net/?f=E_p%20%3D%20%20%5Cfrac%7B1%7D%7B2%7D%20%20%2A%20%20%20m_p%20%20%2A%20%20v%5E2_p)
Here
is the mass of proton with value ![m_p = 1.67 *10^{-27} \ kg](https://tex.z-dn.net/?f=m_p%20%20%3D%20%201.67%20%2A10%5E%7B-27%7D%20%5C%20%20kg)
=> ![8.0*10^{-13} = \frac{1}{2} * 1.67 *10^{-27} * v^2](https://tex.z-dn.net/?f=8.0%2A10%5E%7B-13%7D%20%3D%20%20%5Cfrac%7B1%7D%7B2%7D%20%20%2A%20%20%201.67%20%2A10%5E%7B-27%7D%20%20%2A%20%20v%5E2)
=> ![v _p= \sqrt{\frac{8.0 *10^{-13}}{ 0.5 * 1.67 *10^{-27}} }](https://tex.z-dn.net/?f=v%20_p%3D%20%5Csqrt%7B%5Cfrac%7B8.0%20%2A10%5E%7B-13%7D%7D%7B%200.5%20%2A%201.67%20%2A10%5E%7B-27%7D%7D%20%7D)
=> ![v = 3.09529 *10^{7} \ m/s](https://tex.z-dn.net/?f=v%20%3D%203.09529%20%2A10%5E%7B7%7D%20%5C%20%20m%2Fs)
So
![\lambda_p = \frac{h}{m_p * v_p }](https://tex.z-dn.net/?f=%5Clambda_p%20%3D%20%5Cfrac%7Bh%7D%7Bm_p%20%2A%20v_p%20%7D)
so ![\lambda_p = \frac{6.62607015 * 10^{-34}}{1.67 *10^{-27} * 3.09529 *10^{7} }](https://tex.z-dn.net/?f=%5Clambda_p%20%3D%20%5Cfrac%7B6.62607015%20%2A%2010%5E%7B-34%7D%7D%7B1.67%20%2A10%5E%7B-27%7D%20%2A%203.09529%20%2A10%5E%7B7%7D%20%7D)
=> ![\lambda_p = 1.28*10^{-14} \ m](https://tex.z-dn.net/?f=%5Clambda_p%20%3D%201.28%2A10%5E%7B-14%7D%20%5C%20m)
Answer:
See Explanation
Explanation:
The question is incomplete, as there are no diagrams or options to provide more information to the question.
The general explanation is as follows:
For the object not to move
(1): The forces acting on the object must opposite each other. i.e. if force A acts at the right (or positive direction), force B will act at the left (or negative direction).
(2) The two forces must be equal.
So, for instance:
If the pair of forces are 5N and 5N in opposite directions, the object wil not move.
However, if one of the forces is greater, the object will move towards the direction of the greater force.
Answer:
D. Histogram.
Explanation:
A histogram with equal intervals is suitable here.
The acceleration should 5.4 m/s^2
Answer:
hi mate,
interesting question, first of all the pressure is determined by using the following formula:
Pg = p * G * h
where p is the density of the liquid, G is the gravity and h is the height difference, in you case you have:
p = 1015 kg/m3
G = 9.8m/s2
h = 0.085 m
insert these values into the equation above:
Pg = 1015 kg/m3 * 9.8m/s2 * 0.085 m = 849.81 kg·m-1·s-2 or 849.81 pascal
hope it helps, :-)
please mark me as brainliest