Question

Calcuate the number of grams of solute in 453.9mL of 0.237 M calcium acetate

Answer 1

The number of  grams : 17.082 g

Further explanation

Molarity shows the number of moles of solute in every 1 liter of solute or mmol in each ml of solution

$\large {\boxed {\bold {M ~ = ~ \dfrac {n} {V}}}$

Where

M = Molarity

n = Number of moles of solute

V = Volume of solution

453.9 mL  of 0.237 M calcium acetate

• mol

$\tt mol=M\times V=0.237\times 0.4539=0.108$

• mass

MW Ca(C₂H₃OO)₂ : 158,17 g/mol

$\tt mass=mol\times MW\\\\mass=0.108\times 158.17=17.082~g$