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3 years ago

Why is an alarm clock going "off" when it actually turns on?

Physics

2 answers:

Strike441 [17]3 years ago

6 0

Probaly because of the privouse time that it was on

goblinko [34]3 years ago

3 0

The alarm is going off because the alarm has already been set to activate.

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A 4.4 kg marble (really big heavy marble) is accelerating down an incline. When it reaches level ground it slows down to a stop

KengaRu [80]

Mass=4.4kg

acceleration=-1.74m/s^2

Use newtons second law

$\\ \rm\longmapsto Force=ma$

$\\ \rm\longmapsto Force=4.4(-1.74)$

$\\ \rm\longmapsto Force=-7.656N$

initial velocity=u

Final velocity=v=0

Acceleration=a=-1.74m/s^2

Time=t=1.27s

$\\ \rm\longmapsto a=\dfrac{v-u}{t}$

$\\ \rm\longmapsto u=v-at$

$\\ \rm\longmapsto u=0-(-1.74)(1.27)$

$\\ \rm\longmapsto u=1.74(1.27)$

$\\ \rm\longmapsto u=2.2m/s$

4 0

3 years ago

What latitudes are most likely to see glaciers??

olga55 [171]

Answer : Option D) 90°N and 90°S

Explanation : The latitudes which are given in the options are the angle to be measured in the direction of north and south respectively taking equator as the central line.

When it is 90°N and 90°S it means it forms an right angle and faces towards north and south respectively with respect to the equator, so there are high chances of pointing towards the Arctic and Antarctic regions respectively; therefore giving greater probability of finding glaciers.

7 0

4 years ago

Read 2 more answers

The top of a tower much like the leaning bell tower at Pisa, Italy, moves toward the south at an average rate of 1.4 mm/y. The t

Gemiola [76]

Answer:

$\omega=7.16*10^{-13}\frac{rad}{s}$

Explanation:

The angular speed is given by:

$\omega=\frac{v}{r}$

Here v is the linear speed and r is the radius of the circular motion. The height of the tower is equal to the radius of the circular motion of the top of the tower, since is rotating about its base. We need to convert the given linear speed to $\frac{m}{s}$ :

$1.4\frac{mm}{y}*\frac{10^{-3}m}{1mm}*\frac{1y}{3.154*10^7s}=4.44*10^{-11}\frac{m}{s}$

Now, we calculate the angular speed:

$\omega=\frac{4.44*10^{-11}\frac{m}{s}}{62m}\\\omega=7.16*10^{-13}\frac{rad}{s}$

8 0

4 years ago

Alice kicks a soccer ball with a mass of 2 kg. The ball leaves the ground moving 30 meters per second. What is the kinetic energ

sleet_krkn [62]

By using the formula:

• K.E = ½mv²

mass, m = 2 kg
Velocity, v = 30 m/s

→ K.E = ½ × 2 × (30)² J

→ K.E = (30)² J

→ K.E = 900 J (Answer)

5 0

2 years ago

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Crazy boy [7]

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3 years ago