Ask question

Ask question

All categories

3 years ago

11

Physics help PLEASE 50 points + brainliest for the right answer

1 answer:

Aleonysh [2.5K]3 years ago

7 0

Answer:

the answer is: 3.99 × 10–4 M

Explanation:

You might be interested in

A locomotive accelerates a 25-car train along a level track. Every car has a mass of 7.7 ✕ 104 kg and is subject to a friction f

MaRussiya [10]

To solve the problem it is necessary to apply the concepts related to Force of Friction and Tension between the two bodies.

In this way,

The total mass of the cars would be,

$m_T = 25(7.7*10^4)Kg$

$m_T = 1.925*10^6Kg$

Therefore the friction force at 29Km / h would be,

$f=250v$

$f= 250*29Km/h$

$f = 250*29*(\frac{1000m}{1km})(\frac{1h}{3600s})$

$f = 2013.889N$

In this way the tension exerts between first car and locomotive is,

$T=m_Ta+f$

$T=(1.925*10^6)(0.2)+2013.889$

$T= 3.8701*10^5N$

Therefore the tension in the coupling between the car and the locomotive is $3.87*10^5N$

6 0

2 years ago

What happens to kinetic energy when you increase the mass?

Rus_ich [418]

Increasing mass increases kinetic energy. This can be seen in the equation KE = 1/2 (m) (v)^2

If you found this helpful, please brainliest me!

5 0

2 years ago

An object is 2.0 m in front of a plane mirror. Its image is:?

maria [59]

Planes don’t have mirrors

6 0

3 years ago

Professor Sanchez believes that children acquire language through reinforcement from adults, especially their parents. He believ

MArishka [77]

The answer is “behaviorist”

4 0

3 years ago

An electron is placed 5.40 cm due north of a charged sphere and experienced a force of 8.30 x 10^-13 N due north. What is the el

ira [324]

Answer:

The electric field is $E = 5.1*10^6N/C.$

Explanation:

The force $F$ on a charge $q$ in an electric field $E$ is given by

$F = qE$ ,

which can be rearranged to give

$E = \dfrac{F}{q }$

Now, the force on the electron is $F = 8.30*10^{-13}N$ , and its charge is

$q = 1.6*10^{-19}C$ ; therefore,

$E = \dfrac{8.30*10^{-13}N}{1.6*10^{-19}C}$

$\boxed{E = 5.1*10^6N/C}$

4 0

2 years ago