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xz_007 [3.2K]
3 years ago
10

How many millimetres are in a 4cm

Mathematics
1 answer:
chubhunter [2.5K]3 years ago
4 0
10 mm = 1cm
therefore if you have 4 cm you just multiply 10 x 4
=40 mm
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Suppose that the amount of algae in a pond doubles every 4 hours. If the pond initially contains 90 pounds of algae, how much al
UNO [17]
After 12 hours the pound would have 720 pounds of algae.
4 0
3 years ago
How do you find the y-intercept(b) from the graph? It doesn’t show all values.
Umnica [9.8K]

Answer:

the answer is 42.

Step-by-step explanation:

5 0
3 years ago
If f'(x) = 12x^3 - 2x^2 - 17 and f(1) = 8 , find f(x).
Cloud [144]

Answer:

f(x) =  3x⁴ - \frac{2X^{3} }{3} - 17x +  \frac{68}{3}

Step-by-step explanation:

To find f'(x), we will follow the steps below:

We will start by integrating both-side of the equation

∫f'(x) = ∫(12x^3 - 2x^2 - 17)dx

f(x)  = 3x⁴ - \frac{2X^{3} }{3} - 17x + C

Then we go ahead and find C

f(1) = 8

so we will replace x by 1 in the above equation and solve for c

f(1)  = 3(1)⁴ - \frac{2(1)^{3} }{3} - 17(1) + C

8 = 3 - \frac{2}{3} - 17 + C

C =8 - 3 + 17 + \frac{2}{3}

C = 22 +  \frac{2}{3}

C =\frac{66 + 2}{3}

C = \frac{68}{3}

f(x) =  3x⁴ - \frac{2X^{3} }{3} - 17x +  \frac{68}{3}

7 0
3 years ago
What is the perimeter of the shape below?
Mashcka [7]

None of these choices are correct

The down side of the shape is unknown and cannot be found, therefore you cannot find the perimeter of the shape.

8 0
2 years ago
i need with this math problem. I am confused on how to do it. If you could help me it would be great. There are 2 parts to this
Novay_Z [31]
She took a total of 60 minutes
she answered both mulitiple choice and extended response in the total time which is 60 minutes
she took 2 minutes on rach multiple choice question and 6 minutes for the extended response
let x=number of multiple choice questions
let y=number of extended response questions
we can deduce that
total time =x*2+y*6
60=2x+6y
also we can deduce
20=x+y
since 20 ia the sum of multiple choice and extended response
for part 2 we just solve the system of equations
60=2x+6y
20=x +y
lets multiply the second equation by 2 so we can get rid of x
60=2x+6y
40=2x+2y
subtracting the two equations from each other to yields
20=0 +4y
y=5
to get x we substitute in one of the equations we derived from question 1
x+y=20
substituting y for its value we get
x+5=20
x=15
4 0
3 years ago
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