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motikmotik
3 years ago
6

What is 3.85 times 2

Mathematics
1 answer:
Lilit [14]3 years ago
4 0
To answer this we just need to multiply. 

3.85 × 2 =  7.70

Another way to do this is add 3.85. 
  1 1      (carried 1's)
  3.85
+3.85
----------
  7.7 0

So, 3.85 × 2 = 7.70

Hope I helped ya!! 
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A sample of 125 pieces of yarn had mean breaking strength 6.1 N and standard deviation 0.7 N. A new batch of yarn was made, usin
AlexFokin [52]

Answer:

The 90% confidence interval for the difference in mean breaking strength between the two types of yarn is (0.08N, 0.52N).

Step-by-step explanation:

Before building the confidence interval, we need to understand the central limit theorem and subtraction of normal variables.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Subtraction of normal variables:

When we subtract two normal variables, the mean is the difference of the means, while the standard deviation is the square root of the sum of the variances.

A sample of 125 pieces of yarn had mean breaking strength 6.1 N and standard deviation 0.7 N.

This means that \mu_1 = 6.1, s_1 = \frac{0.7}{\sqrt{125}} = 0.0626

In a sample of 75 pieces of yarn from the new batch, the mean breaking strength was 5.8 N and the standard deviation was 1.0 N.

This means that \mu_2 = 5.8, s_2 = \frac{1}{\sqrt{75}} = 0.1155

Distribution of the difference:

\mu = \mu_1 - \mu_2 = 6.1 - 5.8 = 0.3

s = \sqrt{s_1^2+s_2^2} = \sqrt{0.0626^2+0.1155^2} = 0.1314

Confidence interval:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1 - 0.9}{2} = 0.05

Now, we have to find z in the Ztable as such z has a pvalue of 1 - \alpha.

That is z with a pvalue of 1 - 0.05 = 0.95, so Z = 1.645.

Now, find the margin of error M as such

M = zs

M = 1.645*0.1314 = 0.22

The lower end of the interval is the sample mean subtracted by M. So it is 0.3 - 0.22 = 0.08N

The upper end of the interval is the sample mean added to M. So it is 0.3 + 0.22 = 0.52N

The 90% confidence interval for the difference in mean breaking strength between the two types of yarn is (0.08N, 0.52N).

3 0
3 years ago
In the current year, Brown, a C corporation has gross income (before dividends) of $900,000 and deductions of $1,100,000 (exclud
lyudmila [28]

Answer:

$170,000

Step-by-step explanation:

Gross income is $900,000

Add dividends which is $100,000

Total income is $900,000+$100,000=$1,000,000

Deductions is $1,1000,000.

Note that the deductions is less Dividends Received Deduction (DRD)

Additional deductions due to dividends

Add DRD of which will be 70%  of the dividends received hence 0.7*$100,000= $70,000 since he owned 15% of a Fortune 500 corporation

Total deductions is $1,1000,000+$70,000=$1,170,000

Loss=1,1700,000-$1,000,000=$170,000

Total net loss is $170,000

8 0
3 years ago
Avis Company is a car rental company that is located three miles from the Los Angeles airport (LAX). Avis is dispatching a bus f
pishuonlain [190]

Answer:

Avis Company is a car rental company that is located three miles from the Los Angeles airport (LAX). Avis is dispatching a bus from its offices to the airport every 2 minutes. The average traveling time (round-trip) is 20 minutes.

a. How many Avis buses are traveling to and from the airport?

b. The branch manager wants to improve the service and suggests dispatching buses every 0.5 minutes. She argues that this will reduce the average traveling time from the airport to Avis offices to 2.5 minutes. Is she correct? If your answer is negative, then what will the average traveling time be?

The answers to the question are

a. 10 buses

b. Yes, increasing the fleet by a factor of 4 will reduce the apparent average travel time from the airport to Avid offices from 10 minutes to 2.5 minutes

Step-by-step explanation:

Number of buses dispatched every 20 minutes= 20÷2=10

Therefore 10 Avid buses are travelling to and from the Los Angeles airport

b. By dispatching every 0.5 minutes we have 20÷0.5 = 40 buses.

Since with 10 buses it takes 10 minutes to make the journey from the airport to Avid offices, then it would take 40 buses 10÷4 = 2.5 minutes time to deliver what it took 10 buses, 10 minutes to deliver.

4 0
4 years ago
00.9 0.09 0.9 what come next
kozerog [31]

Answer:

0.009 also as 0 and 9 thousandths

Step-by-step explanation:

6 0
3 years ago
Customers at an ice-cream shop took a survey. The results showed that 144 customers rated the shop as being “very satisfactory.”
eimsori [14]

Answer:

64.8 or 65 Its D

Step-by-step explanation:

7 0
3 years ago
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