1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
N76 [4]
3 years ago
12

Which of the following is a homogeneous mixture? a. Na(s) b. H2O(l) c. Cl2(g) d. NaCl(aq)

Chemistry
1 answer:
iVinArrow [24]3 years ago
7 0

Answer:

H²0 is answer is H20 ok please

You might be interested in
the reaction of Al with HCl to produce hydrogen gas. What is the pressure of H2 if the hydrogen gas collected occupies 14 L at 3
juin [17]

Answer:

Pressure for H₂ = 11.9 atm

Option 5.

Explanation:

We determine the complete reaction:

2Al(s) +  6HCl(aq) → 2AlCl₃(aq) + 3H₂(g)

As we do not know anything about the HCl, we assume that the limiting reactant is the Al and the acid is the excess reagent.

Ratio is 2:3.

2 moles of Al, can produce 3 moles of hydrogen

Therefore 4.5 moles of Al must produce (4.5 . 3) / 2 = 6.75 moles

Now we can apply the Ideal Gases law to find the H₂'s pressure

P . V  = n . R . T → P = (n . R .T) / V

We replace data: (6.75 mol . 0.082L.atm/mol.K . 300K) / 14L

Pressure for H₂ = 11.9 atm

6 0
3 years ago
Read 2 more answers
The buffer solution is used to control the pH to insure that it does not become too high because excessively basic solutions cou
oksian1 [2.3K]

Answer:

pH = 12.7

Explanation:

First, we have to calculate the [Ca²⁺] in a solution of about 250 ppm CaCO₃.

\frac{250mgCaCO_{3}}{L} .\frac{1gCaCO_{3}}{1000mgCaCO_{3}} .\frac{1molCa^{2+} }{100gCaCO_{3}} =2.5 \times 10^{-3} M

Now, let's consider the dissolution of Ca(OH)₂ in water.

Ca(OH)₂(s) ⇄ Ca²⁺(aq) + 2 OH⁻(aq)

The solubility product Ksp is:

Ksp = [Ca²⁺] × [OH⁻]²

[OH⁻] = √(Ksp/[Ca²⁺]) = √(6.5 × 10⁻⁶/2.5 × 10⁻³) = 5.1 × 10⁻² M

Finally, we can calculate pOH and pH.

pOH = -log [OH⁻] = -log (5.1 × 10⁻²) = 1.3

pH + pOH = 14 ⇒ pH = 14 - pOH = 14 - 1.3 = 12.7

5 0
3 years ago
Assume that you measured exactly 2.0 mL of the sodium chloride solution into a small test tube. How many moles of sodium chlorid
Lera25 [3.4K]

Answer:

0.034 mol (4dp)

Explanation:

Use the formula n = m/M where n= number of moles, m=mass in grams and M=molar mass in g/mol.

Therefore to find how many moles, divide the mass in grams (2) by the molar mass of sodium chloride which is 22.99+35.45

4 0
3 years ago
Read 2 more answers
What element has only one proton in its nucleus??
blagie [28]
Hydrogen is the only element in entire periodic table with only 1 proton in its nucleus.
3 0
3 years ago
Answers for both boxes please ​
Elan Coil [88]

Explanation:

\frac{6.900 \times  {10}^{10} }{4.000 \times  {10}^{8} }  \\ 1.725 \times  {10}^{10 - 8} \\ 1.725 \times  {10}^{2}

Hope it will help you :)

3 0
2 years ago
Other questions:
  • What type of waves are sound waves?
    12·2 answers
  • I have a science fair soon and I need to make a interesting experiment but I want it to be easy in the same time. Can you please
    5·2 answers
  • Is carbon dioxide a good absorber of infrared radiation
    9·1 answer
  • Name two air pollutants that bioaccumulate
    8·1 answer
  • key A 0.150 M sodium chloride solution is referred to as a physiological saline solution because it has the same concentration o
    8·2 answers
  • 500.0 ml of 0.110 m naoh is added to 535 ml of 0.250 m weak acid (ka = 6.37 × 10-5. what is the ph of the resulting buffer?
    10·1 answer
  • Which system is responsible for transportation of blood through the system?
    14·2 answers
  • After James Chadwick discovered the neutron, atomic theory expanded to include isotopes. Isotopes have many practical uses. For
    11·1 answer
  • A faulty version of the CFTR gene causes the disease cystic fibrosis (CF). This gene is found in 1 in 25 Caucasians in the Unite
    11·1 answer
  • How many particles are in 2.0 moles of CH4
    14·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!