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jasenka [17]
3 years ago
13

Coffee beans are packaged in 50 kg cartons with an allowable error of 2%. What is the acceptable weight range for a carton of co

ffee beans? *
49 to 51 kg
49.3 to 50.7 kg
46 to 53 kg

pick 1 pls ill give brainleist
43 to 57 kg
Mathematics
2 answers:
Marina86 [1]3 years ago
8 0

Answer:

I think it is B?

Step-by-step explanation:

Hope this helps, I am soooo sorry If I get it wrong.

____ [38]3 years ago
5 0

Answer:

b

Step-by-step explanation:

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5(y - 3) = -2<br>pls answer.​
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y= 2.6

Step-by-step explanation:

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4 years ago
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Work out the value of (2^3)^2
Eva8 [605]

Answer:

2⁶

Step-by-step explanation:

law of indices states multiplication of powers in and out of bracket 3×2=6

6 0
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There has been a great deal of controversy over the last several years regarding what types of surveillance are appropriate to p
alexira [117]

Answer:

Given that a person was identified as a future terrorist, there is a 2.8544% probability that he/she actually is a future terrorist.

Step-by-step explanation:

There are 1000 future terrorists in a population of 300,000,000. So the probability that a randomly selected person in this population is a terrorist is:

P = \frac{1,000}{300,000,000} = 0.000003 = 0.0003%

So, we have these following probabilities:

A 99.9997% probability that a randomly chosen person is not a terrorist.

A 0.0003% probability that a randomly chosen person is a terrorist.

A 98% probability that a future terrorist is correctly identified

A 99.9% chance of correctly identifying someone who is not a future terrorist. This also means that there is a 0.01% probability of someone who is not a terrorist being identified as one.

This can be formulated as the following problem:

What is the probability of B happening, knowing that A has happened.

It can be calculated by the following formula

P = \frac{P(B).P(A/B)}{P(A)}

Where P(B) is the probability of B happening, P(A/B) is the probability of A happening knowing that B happened and P(A) is the probability of A happening.

Here we have:

What is the probability that the person is a terrorist, given that she was identified as a terrorist.

P(B) is the probability that the person is a terrorist. So P(B) = 0.000003

P(A/B) is the probability that the person was identified as a terrorist, given that she is a terrorist. The problem states that the system has a 98% chance of correctly identifying a future terrorist, so P(A/B) = 0.98

P(A) is the probability of a person being a identified as a terrorist. So

P(A) = P_{1} + P_{2}

P_{1} is the probability that a person is a terrorist and was identified as one. So:

P_{1} = 0.000003*0.98 = 0.00000294

P_{1} is the probability that a person is not a terrorist and, but was identified as one. So:

P_{2} = 0.999997*0.0001 = 0.0000999997

So

P(A) = P_{1} + P_{2} = 0.00000294 + 0.0000999997 = 0.000103

The answer is:

P = \frac{P(B).P(A/B)}{P(A)} = \frac{0.000003*0.98}{0.000103} = 0.028544

Given that a person was identified as a future terrorist, there is a 2.8544% probability that he/she actually is a future terrorist.

3 0
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What is the value of x?
Lunna [17]

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2 years ago
Click the pair of numbers that is relatively prime.
7nadin3 [17]
I believe the answer is D. 25 and 27

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