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natali 33 [55]
3 years ago
5

The gas in a closed container has a pressure of 3.00 x 10² kPa 30 ° C. What will the pressure be if the temperature is lowered t

o -172 ° C?
Chemistry
1 answer:
Rainbow [258]3 years ago
6 0

Answer: 100kPa

Explanation:

P1 = 3.00 x 10² kPa , P2 =?

T1 = 30°C = 30 +273 = 303k

T2 = —172°C = —172 + 273 = 101k

P1/T1 = P2/T2

3 x 10² / 303 = P2 / 101

P2 = (3 x 10² / 303) x 101

P2 = 100kPa

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aleksklad [387]

Ionic equation:

\text{H}_2\text{PO}_4^{-} + \text{HAsO}_4^{2-} \to \text{HPO}_4^{2-} + \text{H}_2\text{AsO}_4^{-}

The acid and base in a conjugate pair differ by only one proton \text{H}^{+}. The acid loses one proton to produce a conjugate base, whereas the base gains a proton to produce its conjugate acid.

\text{H}_2\text{PO}_4^{-} loses one proton to produce \text{HPO}_4^{2-} in this reaction.

\text{H}_2\text{PO}_4^{-} \to \text{H}^{+} + \text{HPO}_4^{2-}

Meanwhile, \text{HAsO}_4^{2-} gains one proton to form \text{H}_2\text{AsO}_4^{-}.

\text{HAsO}_4^{2-} + \text{H}^{+} \to \text{H}_2\text{AsO}_4^{-}

Therefore

  • \text{H}_2\text{PO}_4^{-} is the conjugate acid  \text{HPO}_4^{2-}, its conjugate base.
  • \text{HAsO}_4^{2-} is the conjugate base of \text{H}_2\text{AsO}_4^{-}, its conjugate acid.
8 0
3 years ago
Read 2 more answers
A. By referring to forces at work in the atomic nucleus, how can you
qwelly [4]

There is an unstable ratio of protons and neutrons. Because protons are positively charged but neutrons have no charge, an increase in the number of protons means there needs to be an increase in the number of neutrons to "bind" the nucleus together. This is because like charges repel, so the protons will repel each other, and if there aren't enough neutrons to act as "glue" to hold the nucleus together, the nucleus will break apart.

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2 years ago
A common radio wavelength observed coming from astronomical objects is 21 cm. What temperature is associated with this radiation
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Answer:

The temperature associated with this radiation is 0.014K.

Explanation:

If we assume that the astronomical object behaves as a black body, the relation between its <em>wavelength</em> and <em>temperature</em> is given by Wien's displacement law.

\lambda_{max}=\frac{b}{T}

where,

λmax is the wavelength at the peak of emission

b is Wien's displacement constant (2.89×10⁻³ m⋅K)

T is the absolute temperature

For a wavelength of 21 cm,

T=\frac{b}{\lambda _{max} } = \frac{2.89 \times 10^{-3} m.K  }{0.21m} =0.014K

8 0
3 years ago
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Answer:

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a change in the phytoplankton population

a difference in water temperature is the answer

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It is limited by the number of fish eating the phytoplankton directly.

It is limited by the depth of the water in the ocean.  

It is limited by the amount of nutrients in the water.

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They are tiny plants that drift with the currents of the ocean.

They are small plants and animals that exist both on land and in the ocean.

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They are organisms that support all other life in the oceans.

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are the answers

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zooplankton, phytoplankton, large fish, small fish, large shark

phytoplankton, large shark, zooplankton, large fish, small fish

large shark, large fish, small fish, zooplankton, phytoplankton

phytoplankton, zooplankton, small fish, large fish, large shark is the answer

Hope this helps!

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Answer:

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